I=v/r(1-E [negitive exponintial -RT/L])
current
You need to provide values of resistor and inductor etc to find the phase angle.
The resistance of an inductor is generally referred to as the series resistance, sometimes noted as RL. Note that resistance is a DC measurement and that an "ideal" textbook inductor has an RL of 0. The reactance of an inductor is an AC measurement which measures the reaction of a component's current flow to an alternating voltage and is frequency dependent and directly proportional to the inductor's inductance, measured in Henrie's. The impedance is most commonly used when talking about inductors or capacitors and is a combination of resistance and reactance.
The reactance of an inductor depends only on its inductance and the frequency.The voltage and any series components are irrelevant.Z = j 2 pi f L = j 2 pi (100) (0.5) = 314.16 ohmsreactive
The opposition to an alternating current offered by a coil, or inductor, is called impedance (symbol Z, measured in ohms) which, in turn, is made up of two components: resistance (symbol R) and inductive reactance (symbol XL). These three quantities are related as follows: Z2 = R2 + XL2.The resistance of an inductor is a fixed value which depends upon the length of the coil's wire, the cross-sectional area of the wire, and the resistivity of the material from which the wire is made.The inductive reactance of an inductor, on the other hand is directly proportional to the frequency of the supply. So, at high frequencies, an inductor's inductive reactance is very much higher than at low frequencies.So, at high frequencies, the impedance of the inductor is higher because its inductive reactance is higher.The current flowing through a coil is, by Ohm's Law: I = V / Z. So, at high frequencies, the inductor's impedance will be much higher than at low frequencies, which means that a very much smaller current will flow when the frequency is high compare to when the frequency is low.
t = L/R
The time constant for an RL-circuit is equal to L/R. In this case, (0.002 H)/(200 ohm).
You need to convert the inductance value to henry. Then, simply divide the inductance by the resistance.
Simple...(20*10-3)/230=869 microseconds
An inductor will supply better current source.
The stronger the magnetic field on your inductor the greater amount of current you will have flowing through your series circuit.
When you put a light bulb in series with a inductor, the inductive reactance of the inductor reduces the current available to the light bulb, making it less bright. For this effect to be noticed, however, you need a very large inductor. To cut the current in a 60W bulb at 120VAC/60Hz by one half, for instance, you need an inductor around 0.6 henrys.
That depends on the type of circuit you are talking about. Sometimes both an inductor and capacitor are both in parallel with each other. This is called a tank circuit. Sometimes they are both used in series. These are both examples of resonant circuits. Sometimes the inductor can be in parallel with an applied voltage and the capacitor in series. This is a form of high pass filter. On the other hand, the inductor can be in series and the capacitor in parallel to for a low pass filter.
just like it soundsseries resonant has capacitor & inductor in seriesparallel resonant has capacitor & inductor in parallel
because current is same in series resister
Yes, an inductor works with direct current. It is called an electromagnet. Of course, a practical electromagnet has series resistance, otherwise the current in the inductor would increase to the limit of the current/voltage source.
series network consists of components i.e resisters connected end to end. since their is only one path for the flow of current. but potential drop across each resister is different. so thats the reason that series network has maximum resistence then the highest resister in combination. the same amount of current passes through each resister.