The impedance of a component (inductor or capacitor) will change with frequency - resistor impedances will not.
Inductor impedance - j*w*L
Capacitor impedance - 1/(j*w*C)
L = inductance, C = capacitance, j = i = imaginary number, w = frequency in radians
The actual inductance and capacitance does not change with frequency, only the impedance.
That is called "redshift". The frequency of the radiation decreases.
Because Beta (current gain) in a transistor is inversely proportional to frequency. Hence it increases as frequency decreases. Also the ac voltage gain is directly proportional to Beta.
we know that frequency and time period are inversely proportional so as frequency decreases time period increases resulting in larger current flow thus increasing the dissipation.
The oscillator circuit, which is usually quartz crystal controlled with the quartz crystal in a temperature regulated oven to stabilize its resonant frequency.
Frequency is equal to inverse of the square root of density. As the frequency of a string for example goes up the density will go down but in a non-linear fashion. That is to create higher and higher frequencies less and less density decreases are required.
As the wavelength decreases, the frequency of the waves increases. This is because frequency and wavelength are inversely proportional - as one decreases, the other increases, according to the equation: speed = frequency x wavelength.
coupling capacitors are generally used to couple the the AC component of voltage to the DC component(biased voltage) of the transistor amplifier . As we know that the capacitor itself has some reactance which is variable with the applied frequency Rc=1/wc where w=frequency in radians = 2*pi*f and f= frequency of circuit. and, V=VC+VIN VC= voltage drop on capacitor VIN= resultant voltage available for the transistor for amplification so as, frequency increases reactance decreases drop on C decreases so, voltage available for transistor increases and now you can analyse yourself for the case if frequency decreases
As frequency increases, the wavelength decreases and the energy of each photon (in the case of light) increases. Similarly, the period (time taken for one cycle) decreases as frequency increases.
Period and frequency are inverse to each other, as period increases frequency decreases. So, to answer this question as the period of the wave decreases its frequency must increase.
The wavelength of electromagnetic waves decreases as the frequency increases.
When the period of a wave decreases, the frequency of the wave increases. This is because frequency and period are inversely related - as one increases, the other decreases. So, a shorter period corresponds to a higher frequency.
When the frequency of the wave decreases, the pitch of the noise decreases, making it sound lower. The noise may also become more rhythmic or repetitive as the frequency decreases. Additionally, lower frequency noises can travel further distances and penetrate obstacles more effectively.
Wavelength.
The energy increases as the frequency increases.The frequency decreases as the wavelength increases.So, the energy decreases as the wavelength increases.
If the frequency of a vibrating object decreases, the wavelength of the resulting wave also decreases. This is because wavelength and frequency are inversely proportional according to the wave equation: wavelength = speed of wave / frequency. So, as frequency decreases, the wavelength will also decrease to maintain a constant speed of the wave.
The relationship between antenna size and frequency is that as the frequency of a signal increases, the size of the antenna needed to efficiently transmit or receive that signal decreases. This is because higher frequency signals have shorter wavelengths, requiring smaller antennas to effectively capture or emit the signal. Conversely, lower frequency signals have longer wavelengths, necessitating larger antennas for optimal performance.
When the wavelength of light increases, the frequency decreases. Conversely, when the wavelength decreases, the frequency increases. This relationship is described by the equation: frequency = speed of light / wavelength.