You need to divide the 48 volts by the voltage produced by a single battery.
A "C" battery has a 1.5 Volts same with AAA, AA, and D batteries.
One statvolt is about 299.8 volts.
A good AA battery has about 1.5 volts across it.
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
4 volts and how many amps? Watts = amps x volts. It depends on the amount of current (in Amps) flowing at 4 Volts... See Ohms Law: Watts = Volts x Amps If you have 2 Amps flowing at 4 Volts you are dissipating/consuming 8 Watts. If you have 10 Amps flowing at 4 Volts you are dissipating/consuming 40 Watts.
The small batteries (dry cells) used for many electronic devices usually have approximately 1.5 volts. Car batteries (which have several cells working in series) usually have around 12 volts. Other batteries may have other voltages.
22 (1.5 volts each) AA batteries
All regular automobile batteries are 12 volts.
Batteries come with different voltages.
Input is 12 volts. Output can be over 50,000.
24 Volts.
You can hook up an infinitive number of 12 volt batteries in a parallel circuit and still have 12 volts.
A "C" battery has a 1.5 Volts same with AAA, AA, and D batteries.
Yes they can just look at how many volts the battery is that came with the gun if you get to many volts it will destroy the gun.
Fully charged battery should have 12.6 volts. 75% charged 12.4 volts, 50% charged 12.2 volts, & 25% charged 12.0 volts.
Depends on the cell chemistry, which determines the cell voltage. And the degree of charging. Can be anything from 3x1.2 to 3x3.6.
The amperage drawn from batteries is governed by the connected load. The voltage of the batteries can be one of two voltages. in parallel the 8 batteries will give you a voltage of 6 volts. In series the 8 batteries will give you a voltage of 48 volts. The amp/hour capacity of the batteries will give you the amount of current the device can draw over a specific length of time. Equation to fine amperage is I = W/E, Amps = Watts/Volts. Watts = Amps x Volts.