This is made by joining the inputs of a NOR gate. As a NOR gate is equivalent to an OR gate leading to NOT gate, this automatically sees to the "OR" part of the NOR gate, eliminating it from consideration and leaving only the NOT part.
Truth Table
Input A Output Q
0 1
1 0
A+b=
You can use a second gate on the same IC to invert the output (most OR-gate ICs I know of have 4 gates per chip). Do this by tying the output of the first gate to both inputs of the spare gate.
That title of "Universal Gate" is reserved for NAND gates because you can build all possible logic using only NAND logic . You can build even other basic logic like AND, OR and NOT using NAND.
Three 2-input XOR gates and one 3-input NOR gate will do the work. Connect each output of each XOR gate to one input of the 3-input NOR gate and apply the two 3-bit words to the inputs of the XOR gates. If X (X2X1X0) and Y(Y2Y1Y0) are two 3-bit words, X2 and Y2 will connect to one XOR gate, X1 and Y1 to the next XOR gate and X0 and Y0 to the last XOR gate. You could see the result of the operation on a LED connected to the output of the NOR gate. Other implementations are also possible of course. The solution above is absolutely correct, but includes a 3 input gate. If the task is to use only two input gates, then a small change will be needed. Take the outputs from any two XOR gates into a 2 input OR gate. Then take the output of the OR gate and the output of the third XOR gate into a 2 input NOR gate. The operation remains identical to the first solution but adheres to the brief of using gates with 2 inputs. In the real world, there is probably no reason to impose such a limitation on a design so the first solution would normally be the preferred route to take.
NAND gates are universal gates and can be used to construct any of the logic gates (AND, OR, NOT, NOR, XOR, XNOR). The easiest way to figure this out is to use basic Boolean Laws. For instance, to create a NOT gate (A'), tie one of the NAND gate's input to logic high: (A+1)' = A'. To create an AND gate (AxB), use two NANDs in series, with the second one configured as an inverter: (AxB) = ((AxB)')'
super starmon
1. Explain NOR gate as Universal Gate A NOR gate is a simple OR gate with an inverter (NOT gate) at the output. NOR gates are considered Universal Gates because thay can be configured in a few different ways. Connecting the inputs on a NOR gate will result in a NOT gate (inverter). Connecting the above to the output of a NOR gate results in an OR gate.
b'coz t mobility of electrons in NAND gate is 3 times higher than that of NOR gate
an 2 input AND gate can be realize using 3 NOR gates.Let ,A and B are the input and x be the output.x=A.B= NOR(NOR(A) NOR(B))
NOR gate is equivalent to bubbled AND gate. -Nidhi Singh
NOR gate is equivalent to bubbled AND gate. -Nidhi Singh
A+b=
Use 4 NOR gates. For the 1st NOR gate, inputs should be x' and y For the 2nd NOR gate,inputs should be y' and x The outputs of NOR 1 and NOR 2 are taken as inputs of NOR gate 3 The output of NOR 3 is the complemented form of the output required, so, just complement the output of NOR gate 3 with another NOR gate and Viola!, you have your HALF ADDER OUTPUT PS:I have used a double rail logic, where both x:x' and y:y' are available
Yes._____A----|_____NOR------QThis is an inverter. A NOR gate is an OR gate with an inverter on the end, so adding the above configuration after another NOR gate would give you an OR gate.__A----|__NOR---\__ NOR------QB----|__NOR---/This is an AND gate. By adding the inverter, you can get a NAND gate.A____|___|__NOR----------------\| | \| |___ NOR----QB __| |___NOR-----\ /|_____ NOR --/|_____NOR-----/By combining an AND gate, an OR gate, and a NAND gate, and canceling out a couple of inverters, you get this operator, which is a XOR gate.The formatting here is messed up, but if you go to the "improve answer" link, you can see the circuits.
A 2 input NAND gate requires 4 NOR gates.A 3 input NAND gate requires 5 NOR gates.A 4 input NAND gate requires 6 NOR gates.etc.
nor to and
In grammar, it is a negative "or", as in "It is neither fish nor fowl" In logic circuitry, it is a "not or" gate, which is the inverse of an "or" gate