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If the voltage has a peak value of 100v what is the rms value of the voltage?
Wiki User
∙ 12y ago
Peak values times 0.707 gives the RMS value.
This question cannot be answered without knowing the waveform of the voltage.
If it is continuous direct current rms value is 100V.
If it is a sine wave (like house current), the rms value is 100/ (sq. root(2)) or 70.7V approx.
For a regular series of square pulses, it is 100V times the mark/(mark+space) ratio.
Any other waveform, you need to calculate the root mean square value of the function. ( Square, integrate and take square root over one complete period.)
If all the above fail, measure the heating effect in a 40K resistor. It will be 0.25 Watt or less - calculate from the result.
Wiki User
∙ 12y ago
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What is the difference of peak and rms value?
RMS stands for "Root of the Means Squared", and is a mathematical method of defining the "operating" voltage of a sine wave power source. Typical home lighting and outlet voltage presently is 120 VAC (volts alternating current), 60 Hz. (Hertz, formerly referred to as "cycles per second".) But the PEAK voltage is the absolute maximum voltage at the "peak" of each sine wave of voltage. Mathematically, the "Peak" voltage is 1.414 (which is the square root of the number 2) times the RMS voltage, and conversely, the RMS voltage is 0.707 times the PEAK voltage.
What is the relationship between RMS and peak voltage for a square waveform?
RMS and peak voltage for a square waveform are the same. There is a small caveat, and that is that you'd have to have a "perfect" square wave with a rise time of zero. Let's have a look. If we have a perfect square wave, it has a positive peak and a negative peak (naturally). And if the transition from one peak to the other can be made in zero time, then the voltage of the waveform will always be at the positive or the negative peak. That means it will always be at its maximum, and the effective value (which is what RMS or root mean square is - it's the DC equivalent or the "area under the curve of the waveform") will be exactly what the peak value is. It's a slam dunk. If we have a (perfect) square wave of 100 volts peak, it will always be at positive or negative 100 volts. As RMS is the DC equivalent, or is the "heating value for a purely resistive load" on the voltage source, the voltage will always be 100 volts (either + or -), and the resistive load will always be driven by 100 volts. Piece of cake.
What is the conversion for rms voltage to peak to peak voltage?
For sine waves:To calculate the RMS value of a sine wave, multiply the peak value by 0.707. The peak value is, of course, one half the peak-to-peak value. To go the other way, reverse the order of operations. That is, if you're starting with an RMS value, divide by 0.707 and then multiply by two to get the p-p value. Another way to convert from RMS to p-p is to multiply the RMS value by two square roots of two: RMS x 2 x SQR(2).Or more simply, to convert from RMS to peak to peak voltage:(RMS x 1.414) x 2=P-PFor example:120vac x 1.414= 170vac169.68vac x 2 = 339.36vac P-PWhere there is a significant reactive component in the characteristic of the cabling or load, we must also consider the effects of the X/R ratio. The real vs imaginary components of the impedance:V(peak) = V(rms) * sqrt(2) * (1+ e(exp -pi/(X/R)))where "exp" is the exponent to which the value of e is raised.Reading the power of e above in English:"e to the power of (minus pi divided by the X/R ratio)".Take careful note of the top line of the first answer "For sine waves". More specifically the formula applies only to a signal which is a pure sine wave (a single frequency, no harmonics or other frequencies). As soon as you combine two or more sine wave signals of different frequencies, the ratio of peak voltage to RMS voltage depends strongly on the phases of the component signals. Too complicated to answer here, in full explanation.Vrms = (Vp-p / 2 )/ sq.root (2) = Vp-p / 2.828 for sinusoidal waves..*Note: If the signal or the waveform is not sinusoidal you'll have to derive from basic steps with a sound knowledge about integrations.RMS = root mean square = square root (mean(square values of voltages))
The average value of a single sine wave of AC is 42.5amps. what is rms value?
Average Current = 0.636 * (Peak Current)so Peak Current = (Average Current)/0.636RMSCurrent = 0.707 * (Peak Current)so Peak Current = (RMS Current)/0.707Because both equations are in terms of Peak Current, we can set them equal to each other.(Average Current)/0.636 = (RMS Current)/0.707(42.5)/0.636 = (RMS Current)/0.707thenRMS Current = (0.707)(42.5)/0.636 = 47.24 ampsAnother AnswerSince the average value of a single sine wave is zero, you cannot calculate its r.m.s. value!
What is RMS in electricity?
RMS stands for Root Mean Square. Power is calculated as V2/R where V is the voltage and R is the resistive component of a load, This is easy toi calculate for a DC voltage, but how to calculate it for a sinusoidal voltage? The answer is to take all the instantaneous voltages in the sine wave, square them, take the mean of the squares, then take the square root of the result. This is defined as the "heating effect voltage". For a sine wave, this is 0.707 of the peak voltage.
A technician uses an oscilloscope to measure the peak value of an ac wave he tells you that the voltage has a peak value of 100v what is the rms value of the voltage?
100v divided by 1.41
How do you change dc values to ac values?
To convert DC values to AC values if you are wanting RMS values they are the same. 100V DC and 100V AC (RMS) are the same "value". If you want to know the Peak-To-Peak AC value you would multiply the RMS value by 1.414. So 100V AC RMS equals 141.4 V Peak to Peak.
A sine wave with an RMS value of 100 v would have a peak value of?
For a sine wave ONLY - and assuming you are talking plus and minus 100V (200V peak to peak) - the RMS voltage is about 71V. (One half square root of 2 * single sided peak value)
What is the peak voltage of a sine wave that measure 220V AC rms?
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
What is the rms value for 300mv peak to peak?
Its 0.7 times peak-0 voltage, 106 mv RMS.
What is the peak-to-peak voltage in a circuit with an rms voltage of 120VAC?
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
Peak voltage 100volts what is rms value?
70.7
Household supply of 230volts is rms value or maximum value of voltage?
When you say holdhold supply of 230volts, you are referring to the RMS value, not the peak value.
Convert rms to peak to peak power?
P-P voltage = RMS voltage * 2 * sqrt (2)Here's an example: house voltage is 120VRMS, which is actually ~169 volts peak - neutral. double this will give peak to peak value.
What is peak to peak voltage?
Conversions of RMS voltage, peak voltage and peak-to-peak voltage. That are the used voltages. The expression "average" voltage is used for RMS voltage.Scroll down to related links and seach for "RMS voltage, peak voltage and peak-to-peak voltage".Answer'Average' is not the same as 'root mean square'. As the average value of a sinusoidal voltage is zero, you cannot convert it to a peak-to-peak value.
What is difference between amplitude and peak value?
It is the highest value of the amplitude, called the peak value. Scroll down to related links and look at "RMS voltage, peak voltage and peak-to-peak voltage". Look at the figure in the middle below the headline "RMS voltage, peak voltage and peak-to-peak voltage".
How rms voltage related to peak voltage?
The average voltage is the rms voltage.Volts peak = volts RMS times 1.414Volts RMS = volts peak times 0.7071Use the link below to an RMS voltage, peak voltage and peak-to-peak voltage calculator.********************************The average voltage is not the r.m.s. voltage.The average voltage of a sine wave is 0.636 x the peak value. Conversely, peak voltage is 1.57 the mean or average.
