Depends on how you add them. Added in series, the voltage will increase, maybe to the point of damaging the LED. If the LED survives, it will shine brighter.
Added in parallell, the LED will shine the same, and will be able to shine longer before draining the batteries.
there are chances of more heat loss in the circuit.
It depends on how you add them. The current or the voltage can be increased. However this may damage components in the circuit.
stay the same
decrease
increase
Yes, but the 9V can't deliver as much current as the AA can. Internally a standard 9V contains 6 AAAA batteries. It would be best to use all AAAA cells or all AA cells, depending on current requirement of the load.
The power dissipated by the complete circuit, no matter whether it's a series or parallel one, is the simple sum of the power dissipated by each component of the circuit.
The 80% ideal is from the NEC. Let's say you have a standard 15A circuit. This circuit is rated to carry a maximum of 15A, no more. If you try to draw more than 15A, the breaker will pop. Now, you can put 15A worth of appliances on this circuit, but then you are running it at its maximum all the time. If you add anything else to this circuit, you will pop the breaker. If you have something that draws surge current, it can opo the breaker under normal use. You have no "wiggle room" when you load it at its maximum. Also, as touched on above, if you run your circuit at the maximum you cannot add anything else. This is generally a sign that you need to upgrade your wiring. Furthermore, the breaker can handle 15A indefinitly under standard test conditions, which are close to ideal. Your breaker box may not be ideal. Breakers are thermal devices, so self heating and heating from other breakers can be a problem. If your breaker is hot, it will pop sooner than if it is cold. The more current that flows through it, the hotter it will get. If you are overloading circuits the easiest thing to do is to break the circuit up into multiple circuits. The exact implementation will depend on the situation.
In a DC parallel circuit, equal voltage is applied to each device that is connected in parallel. For example, if three devices are connected in parallel to a 9 volt battery, each device will have 9 volts applied to it. In a DC series circuit, the sum of the voltage drops across each device connected in series equals the source voltage. So say you have three devices connected in series, and they are connected across a 9 volt battery. Each device will have less than 9 volts across it, but if you add the voltage drops across each device togther, it will equal 9 volts. Batteries in series have an additive effect to the voltage. A single AA battery has 1.5V. Two in series will have 3.0V. Batteries in parallel do not experience an additive effect to voltage. To answer this question briefly there is a big difference. The major difference is the resistance the circuit offers when the same components are wired in series or parallel. I do not know how much you want to know, but resistance of a component is measured in Ohms. An easy way to think of ohms is how much force or energy is required to move an object. The less ohms a circuit has the more it can do with the same amount of energy, which in some cases can be a bad thing. To move on, lets say you have two light bulbs, to give a cliche example, and both are 2 ohm load. Now if you wired these two light bulbs in series, connect positive of one bulb to negative of the other and then the others to a battery, the bulbs would be half as bright as one bulb to the same battery. Yet if you wired these in parallel there brightness would be the same as if one light bulb was connected to the circuit. This is because the voltage in the parallel circuit doesn't decrease when you add a light bulb, whereas on the series circuit it does decrease. Hope that helps
If by capacities you mean voltages then they will add in series and have the voltage of the lower one in parallel. Putting them in parallel will generate alot of heat because the wire acts as resistor to allow the current to drop from the first battery to the second.
That will depend on whether they are added in series or parallel.
It gets brighter and brighter - until it burns out.
We did this experiment in class, the more batteries added, the brighter the bulb will become!
The voltage stays the same but the amp hours capacity increases.
death 2 the bulb
Putting batteries in series will up the voltage of the entire circuit. Certain things need higher voltage, so you put your batteries in series. Putting batteries in parallel will not up the voltage, but will let the current last longer. Watches would be more of an example for that. You want watch batteries to last long.
Voltage remains constant; current increases.
If you add a second resistor, the resistance of series circuit will increase.
You need to multiply the number of coulombs by the number of volts. If the two batteries are in series, then you can add the voltage of both batteries.
"http://www.tpub.com/neets/book1/chapter3/1-26.htm" This site explains how to calculate the resistance, but it decreases the resistance when you add more.
When you have multiple loads in a series, the resistance of the loads is added together allowing very little current to flow through the circuit to power any of the loads, making for a low amperage circuit. If you have your loads in parellel, the resistance of the loads in the circuit is subtracted which allows more current to flow, making for a high amperage circuit.
If the two batteries are in series, add the voltages. Then use Ohm's Law to calculate the current (that is, divide the voltage by the resistance).