Over 9000.
The height of the ball after 3 seconds can be calculated using the formula for free fall: ( h = h_0 - \frac{1}{2} g t^2 ), where ( h_0 ) is the initial height (80 meters), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( t ) is the time in seconds. After 3 seconds, the height is ( h = 80 - \frac{1}{2} \times 9.81 \times (3^2) ), which simplifies to ( h = 80 - 44.145 ). Therefore, the height of the ball after 3 seconds is approximately 35.855 meters.
65
Yes
To determine how long it took King Kong to fall from a height of 320 meters, we can use the formula for free fall: ( t = \sqrt{\frac{2h}{g}} ), where ( h ) is the height (320 m) and ( g ) is the acceleration due to gravity (approximately 9.81 m/s²). Plugging in the values, we find ( t \approx \sqrt{\frac{2 \times 320}{9.81}} ), which calculates to about 8.06 seconds. Thus, it would take King Kong approximately 8.06 seconds to fall straight down from the top of the building.
weight- 55-65 pounds height- 2ft-3ft
We can't tell the height; but the distance between the top and the bottom is 578.7 feet. (rounded)
One minute is equal to 60 seconds, so 65 seconds is longer than one minute by 5 seconds. Therefore, 65 seconds is more than 1 minute.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
Terminal velocity is typically reached within 10-12 seconds when falling from a height, depending on factors such as air resistance and the height of the fall.
Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters
2051244000 seconds
2,051,200,190 seconds.
The height of the ball after 3 seconds can be calculated using the formula for free fall: ( h = h_0 - \frac{1}{2} g t^2 ), where ( h_0 ) is the initial height (80 meters), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( t ) is the time in seconds. After 3 seconds, the height is ( h = 80 - \frac{1}{2} \times 9.81 \times (3^2) ), which simplifies to ( h = 80 - 44.145 ). Therefore, the height of the ball after 3 seconds is approximately 35.855 meters.
3600 / 65 = 55.384615
On object falling under the force of gravity (9.8 m/s2) would, in a vacuum, fall a distance of 706 metres in 12 seconds. In a non-vacuum, i.e. air, the object would fall less distance in the same time due to drag.xt = 0.5 (9.8) t2
1 hour = 3600 seconds 3600/65 = ~55.38 seconds
Seat height is 29.5 inches.