It is a the current drawn by the application that is connected to the power source
load
inductive load does not allow the current to become zero eve though the supply source get removed . inductive load reduce the power factor . they does not allow sudden change in current in the load ...
Full load current can be calculated by the formula given below: P=SQUARE ROOT OF 3*V*I*POWER FACTOR P=1.732*V*I*PF suppose 3 kw motor three phase voltage assuming .85 power factor and 415 volt full load current will be 3*1000=1.732*415*I*.85 I=4.9 ampere(full load ampere)
An increase in load (equivalent to a decrease in resistance*) causes an increase in load current. This increases the internal voltage drop within the transformer, and the terminal voltage reduces accordingly.[*An increase in load means more current is being drawn by that load, so an increase in load is equivalent to a decrease in load resistance]
resistive loadAnswerIf the current is driving a motor, then the load is resistive-inductive.
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
2 to 5% of full load current
Load!
load
No load current is mostly inductive, hence the load current may not be a sine wave
As the no load current is the current due to core losses of the motor which is very small .in no load terminals are open circuited no current flows through it, a small current flows which is due to core
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
If no current flows through a load, then no energy is received by the load. Energy is transferred through the flow of current, so without any current, there is no energy transfer to the load.
This is the current flowing in the primary circuit when full-load current flows in the secondary circuit.
A load increases the flow of electrical current in a series circuit. No load, no flow.
The secondary load current will change. This, in turn, will cause the primary current to change (the primary current being the phasor sum of the [IS (Np/Ns)] and the primary current (Io).
The starting current of any electrical equipment which is 6 times more than that of the full load current. ex: full load current = 5 A the starting current will be 5*6 = 30 A.