K2SO4(aq) + SrI2(aq)=SrSO4(aq) + 2kI(aq)
Sr + 2 H2O -> Sr(OH)2 + H2
2Sr(NO3)2 → 2SrO + 4NO2+ O2
Because strontium sulfate is much less soluble in water than strontium chloride, sodium chloride, or sodium sulfate, this reaction is: Na2SO4 (aq) + SrCl2 (aq) => 2 NaCl (aq) + SrSO4 (s).
SrBr2 + (NH4)2CO3 → SrCO3 + 2NH4Br Strontium Bromide + Ammonium Carbonate → Strontium Carbonate + Ammonium Bromide
You wouldn't expect strontium to gain electrons in a chemical change.
The reaction between strontium and nitrogen gas (which has the formula N2) produces strontium nitride, which has the formula Sr3N2. The balanced equation is: 3Sr + N2 -> Sr3N2. If there is an excess of oxygen available, the balanced equation for reaction between indium and oxygen is: 4 In + 3 O2 -> 2 In2O3.
A reaction doesn't occur.
4K + O2 = 2K2O so the "coefficient" is 1
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
potassium
Sr + 2 H2O -> Sr(OH)2 + H2
H2SO4 + 2KOH = K2SO4 + 2H2O
HCl + KOH ==> KCl + H2O
Yes, I know strontium iodate does.
This reaction is:2 KClO3 = 3 O2 + 2 KCl
2KClO3 ----> 2KCl + 3O2
Kn2 heat equal kn2+o2