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What is the orbital period of an imaginary satellite orbiting just above Venus' surface?
The orbital speed of a body with negligible mass compared to the central one,
in a circular orbit, is
v = square root of ( G M/R ) G = the universal gravitational constant = 6.67 x 10-11nt-m2 / kg2
M = mass of the central body; Venus' mass = 4.8676 x 1024 kg (0.815 of Earth)
R = radius of the orbit; Venus' mean radius = 6,051.8 km
The distance around a surface-skimming orbit is the planet's circumference.
C = (2 pi R); Venus's circumference = 12,103.6 x 103 pi
The period is 12,103.6 x 103 pi/v
The whole mess, all in one, is
T = C sqrt(R/G M)
T = (12,103.6 x 103 pi) sqrt(6051.8 x 103/6.67 x 4.8676 x 1013) . From that, I get T = 5,296.7 seconds = 1hr 28min 17sec
To check it, the only thing I have to compare it with is that, from my half-vast
trove of useless knowledge, I know the corrresponding period for Earth to be
86 minutes = 1hr 26min. I learned that when Sputnik-1 launched while I was in
high school.
Being at a radius 0.95 as large, around 0.815 as much central mass, the
1:28 that I got seems reasonable, at least within an order of magnitude.
What else can I help you with?
If a satellite orbiting just above the surface of the Earth orbits in about 1.5 hours then at about how many Earth radii from the Earth's center must a satellite orbit to have a period of 24 hours?
You can use Kepler's Third Law to calculate this.
At what height from the surface of the earth the total energy of the satellite is equal to its potential energy at a height of 2R from the surface of earth?
This question cannot be answered because:the total energy of the satellite includes its kinetic energy and that depends on its orbital speed. This is not specified;it is not clear what you mean by "potational": is it a typo for rotational or potential?what is R? The radius of the earth or the height of the satellite or some other measure?
What is non-geostationary satellite?
A geostationary orbit is an orbit of the Earth that is circular, over the equator, and at the right distance to have a period of 24 hours. A satellite in such an orbit appears to hang motionless, always at the same point in the sky Anything else is a non-geostationary orbit. A satellite in one of those appears to move in the sky, so that if you want to communicate with it, you need a movable dish.
A satellite is at an altitude of one of earth radius. How does the gravitational force on the satellite compare to the force if it were on the surface of earth?
Since the distance from the Earth's center is doubled, the force will be reduced by a factor of 4.
Why are satellite orbits depicted as sine-wave shapes?
The sine wave represents 360 degrees or a full circle. As the satellite revolves 360 degrees around the earth in its orbit this is how it is represented on a flat surface.
Why scientist must carefully set the right orbital speed of a satellite orbiting earth?
Scientists must carefully set the right orbital speed for a satellite that will be orbiting Earth, so that it will orbit correctly. The wrong speed will have the satellite move too fast, or too slow, skewing information and possibly causing the satellite to fall out of orbit and back to the planet's surface.
What would be the orbital speed and period of a satellite in orbit 1.44 times 10 to the power of 3m above earth?
The orbital speed would be approximately 7.63 km/s and the period would be approximately 95.59 minutes for a satellite orbiting Earth at an altitude of 1.44 x 10^3 m. These values can be calculated using the formula for orbital speed (v = √(GM/r)) and the formula for orbital period (T = 2π√(r^3/GM)), where G is the gravitational constant, M is the mass of Earth, and r is the altitude of the satellite above Earth's surface.
The planet closest to the sun to have satellite?
Venus has two artificial satellites orbiting it, radar-mapping the surface and gathering other useful information about its surface.
Is an orbiting satellite has a diameter of 60 cm what is the total surface area of the satellite?
60 cm diameter sphere area = pi x 602 cm2 = 11310 cm2 = 1.131 m2
Mars rotates on its axis once every 24.8 hours What is the speed of a geosynchronous satellite orbiting Mars?
The speed of the satellite is dependant on its distance from the surface of the planet. the greater the altitude, the greater the speed, or velocity. I would think that Velocity Equation would be a simple linear equation of the form; y=kx, where k is a constant. What that constant is for Mars, I do not know as I did not do Astronomy at Uni, only Physics subjects.
If a satellite orbiting just above the surface of the Earth orbits in about 1.5 hours then at about how many Earth radii from the Earth's center must a satellite orbit to have a period of 24 hours?
You can use Kepler's Third Law to calculate this.
What is orbiting the earth and taking pictures of it?
A satellite is orbiting the Earth and taking pictures of it. Satellites are equipped with cameras that capture images of Earth's surface for various purposes, such as weather monitoring, environmental analysis, and mapping.
What is a satellite starting with m?
Mimas is a large moon of Saturn. Metis is a moon around Jupiter.
What is the difference between a Landsat satellite and a GOES satellite?
Among one of many differences is that Landsat is Polar-orbiting while GOES is geostationary. This also means that GOES is much further above the surface, so the resolution is poorer.
What satellite is orbiting mercury?
Mercury has no known moons (or natural satellites) and has no manmade satellites orbiting it either. It was visited in the 1970s buy a man made probe called mariner 10, which made three passes to observe and map it's surface.
What satellite went to moon recently?
The Lunar Reconnaissance Orbiter (LRO) is a satellite that has been orbiting the Moon since 2009, collecting valuable data and images of the lunar surface. It is part of NASA's ongoing exploration of the Moon.
What is orbital time period of geostationary satellite?
The orbital time period of a geostationary satellite is approximately 24 hours, specifically about 23 hours, 56 minutes, and 4 seconds. This allows the satellite to maintain a fixed position relative to a point on the Earth's surface, as it orbits the Earth at the same rotational speed. Geostationary satellites are positioned at an altitude of about 35,786 kilometers (22,236 miles) above the equator.
