The transfer rate of an eight-track magnetic tape can be calculated by multiplying the speed by the density. In this case, the transfer rate would be 120 inches per second x 1600 bits per inch, resulting in a transfer rate of 192,000 bits per second. This means that the tape can transfer data at a rate of 192,000 bits per second.
By unit of length and distance and conversion ,we can say that 1 feet =12 inches 6 feet = 72 inches 6'3'' =75 inches
To compare the lengths, we can convert everything to inches. Two yards is 72 inches (2 yards × 36 inches/yard). Five feet is 60 inches (5 feet × 12 inches/foot), and 5 feet 10 inches is 70 inches (60 inches + 10 inches). Therefore, 2 yards (72 inches) is the longest, followed by 5 feet 10 inches (70 inches), then 68 inches, and finally 5 feet (60 inches).
12 inches- 1 foot 24 inches- 2 feet 30 inches- 2 feet 6 inches 34 inches 2 feet 10 inches.
By unit of length and distance and conversion ,we can say that 1 feet=12 inches 7 feet = 12 * 7=84 inches
54 inches (12 inches in a foot and then add 6 inches to make up 4'6)
1728000bits/
The transfer rate for this nine-track magnetic tape unit is 120 inches per second x 1600 bits per inch x 9 tracks = 1,728,000 bits per second or 1.728 Mbps.
The formular is: Number of bytes on a track x Rotation time Therefore, Transfer rate = 1600 x 120 = 192000ms/track
The density is 128 and an eighth grams per cubic inch.
In addition to volume, density depends on mass. There is no information about mass in the question.
Magnetic tapes are usually used for data storage. The length of a magnetic tape is 10.5 inches
110 inches = 2,794 millimeters.
It is approx 0.79 inches.
You multiply x inches by 2.5 to get centimeters.
30 lbs
39.5 millimeters is 1.56 inches.
33mm converts to 1.3 (1.29921) inches.