we know,
v=IR
resistor, capacitor, inductor and other electrical components have their own specific characteristics to drop voltage or to consume voltage at a fixed amount.
the supplied voltage produces a current that changes with the change of the voltage. It doesn't changes simultaneously. so the voltage change across the components. but the current doesn't changes across component...
AnswerThink of a circuit with several loads as being rather like a number of central heating radiators connected in the same way. The same water (current) flows through each radiator. In order for that water to flow, we need a pump to supply pressure (supply voltage) across all the radiators. At the same time, there must also be a pressure difference (voltage drop) across each individual radiator or the water wouldn't flow through it. The sum of these individual pressures must add up to equal the pressure supplied by the pump.
So the same current flows through individual loads, driven by the supply voltage applied across the entire circuit. At the same time, there must also be voltages across individual loads (called 'voltage drops'), or current wouldn't be flowing through them. The sum of the individual voltage drops will equal the supply voltage.
Capacitors resist a change in voltage. It takes current to effect a voltage change, resulting in the current "leading" the voltage. Similarly, inductors resist a change in current. It takes voltage to effect a current change, resulting in the current "lagging" the voltage.
EMF is the voltage across a coil (or motor) due to changes in the magnetic field. If you change the current the coil will generate a voltage (in the opposite direction of the current). So it is not the field but the change that matters.
It might mean that the voltage across a capacitor cannot change instantanteously because that would demand an infinite current. The current in a capacitor is C.dV/dt so with a finite current dV/dt must be finite and therefore the voltage cannot have a discontinuity.
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
no it is not possibleAnswerYes, by changing the voltage OR the resistance.
In an LC circuit, the current and voltage are related by the equation V L(di/dt) Q/C, where V is the voltage across the components, L is the inductance, C is the capacitance, Q is the charge, and di/dt is the rate of change of current. The current in the circuit is directly proportional to the rate of change of voltage across the components.
When a current flows through a capacitor, the voltage across it increases or decreases depending on the rate of change of the current. If the current is constant, the voltage remains steady. If the current changes rapidly, the voltage across the capacitor changes quickly as well.
A: In a series circuit the current remains the same for each components only the voltage across each component will change and only if the components are of different value.
due to change in flux
Current changes across a resistor in direct proportion to the voltage applied. This relationship is described by Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), or I V/R.
In a capacitor, the current LEADS the voltage by 90 degrees, or to put it the other way, the voltage LAGS the current by 90 degrees. This is because the current in a capacitor depends on the RATE OF CHANGE in voltage across it, and the greatest rate of change is when the voltage is passing through zero (the sine-wave is at its steepest). So current will peak when the voltage is zero, and will be zero when the rate of change of voltage is zero - at the peak of the voltage waveform, when the waveform has stopped rising, and is about to start falling towards zero.
The relationship between capacitor current and voltage in an electrical circuit is that the current through a capacitor is directly proportional to the rate of change of voltage across it. This means that when the voltage across a capacitor changes, a current flows to either charge or discharge the capacitor. The relationship is described by the equation I C dV/dt, where I is the current, C is the capacitance of the capacitor, and dV/dt is the rate of change of voltage with respect to time.
Capacitors resist a change in voltage. It takes current to effect a voltage change, resulting in the current "leading" the voltage. Similarly, inductors resist a change in current. It takes voltage to effect a current change, resulting in the current "lagging" the voltage.
A: In series circuit the current remains the same no matter how many components are in series. just the voltage will change to reflect different voltage drops for each.
Capacitors resist change in voltage. By definition, the equation is dv/dt = i/c, or rate of change of voltage in volts per second is current in amps divided by capacitance in farads. In order for the voltage to change instantaneously, then dv/dt must be infinity, which means i/c is also infinity. If capacitance is non-zero, then current must be infinity. Since there is no perfect voltage source, or no resistor or wire with perfect zero ohms, then it is impossible to have an infinite current, so it is impossible for the voltage across a capacitor to change instantaneously.
Compute the open load voltage of the current source across its shunt resistance.This voltage becomes the voltage source's voltage.Move the current source's shunt resistance to the voltage source's series resistance.Insert the new voltage source into the original circuit in place of the current source.
A high current flows through a short circuit even if there is no voltage change because the resistance across the short circuit is zero.