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Use Wade's rules: Total no. electrons is (6 x Co) + (16 x CO) = (6 x 9) + (16 x2) = 86 electrons. Assume 12 e are used for each metal fragment for bonding to ligands, ie 72 electrons which leaves 14 electrons for cluster (ie M-M) bonding. In crude terms this can be seen as 7 M-M bonds distributed across the cluster, although a multicenter bonding view with 14 e across all M-M vectors is far more appropriate.

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