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What does NAND stand for?
NAND stands for 'Not And', which means the output will send a signal so long as both inputs aren't on. (If both inputs A and B are 1, then the output is 0. All other combinations give an output of 1)
What are the notes for clarinet imperial march theme song?
e, e, e, c, g, e, c, g, e, b, b, b, c, g, eb, c, g, e
Is it possible to raise a F to a B in one week of school?
Possible, yes. Probable, no. If you have tests and quizzes and do all your home work and class work, and depending on your grading scale, if you got a 100 on everything, maybe. It depends on how many tests you've taken before and after that "F". For instance, let's say an A=5, B=4, C=3, D=2, and F=1. If you got that F on just ONE previous test, then you have to get the 1(F=1 remember) up to a 4(B=4). If you have one F and one A you have a total of six(1+5)Now divide that by 2(number of tests)and you get 3, not a B.(4) Now take another test and get an A, and you have 5+5+1=11(A+A+F) Now divide that by 3(number of tests) 3.67 is close to a B(4). So let's try another test and you get an A. Now we have three A's and an F.(5+5+5+1) Now add that up and divide by 4(4 tests) and there's your B. So unless you take four tests and get A's, you won't get that B.That's assuming you got your F on only ONE test. Otherwise, things change again.
What are the notes of the febreze jingle?
(All notes listed are according to treble clef) Whistling: (All notes are natural) B, D, E, D Bass: (Also all notes are natural) G, G, B, B, C, C, D Vocal: B, B flat, B, C, B, B flat, B, D
What are the notes to crazy train on the bagpipes?
Doubling on all. B d a b d e b d a b d e all i got sorry
Can a woman who has B positive blood and a man who has AB- blood have a child with AB positive blood?
My understanding is that the blood type and Rh factor are independently inherited, so that all the combinations are possible: B+, B-, AB+, and AB-
How many combinations can be made using 5 A's and 4 B's?
20
There are Ten questions with a possible A B C answer Only seven questions have to be answered How many combinations are there?
21
How many combinations of 6 numbers are there in 16 numbers What are these combinations?
There are 16C6 combinations = 16!/(6!(16-6)!) = 16!/(6!10!) = 8,008 possible combinations. Assuming the 16 numbers are the hexadecimal digits 0-F, they are: {0, 1, 2, 3, 4, 5}, {0, 1, 2, 3, 4, 6}, {0, 1, 2, 3, 4, 7}, ...., {0, 1, 2, 3, 4, E}, {0, 1, 2, 3, 4, F}, {0, 1, 2, 3, 5, 6}, ..., {0, 1, 2, 3, 5, F}, {0, 1, 2, 3, 6, 7}, ...., {0, 1, 2, 3, 6, F}, ...., {0, B, C, D, E, F}, {1, 2, 3, 4, 5}, ..., {9, A, B, C, D, E}, {9, A, B, C, D, F}, {9, A, B, C, E, F}, {9, A, B, D, E, F}, {9, A, C, D, E, F}, {9, B, C, D, E, F}, {A, B, C, D, E, F} I'll let you fill in the missing 7,990 possible combinations.
What is the probability of rolling an odd number OR getting a heads when rolling a die and tossing a coin?
To find the probability that when rolling a die and tossing a coin, your will obtain an odd on the die OR a heads on the coin, use the addition rule, which is: P(A) + P(B) - P(A and B) = P(A or B In this example, event A is tossing heads on the coin, and event B is rolling odd on the die. What you are trying to solve is actually A U B (A union B) First the sample set of all 12 possible combinations: S={H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6} The 6 heads possible combinations are: A={H1, H2, H3, H4, H5, H6| The 6 odd number possible combinations are: B={H1, H3, H5, T1, T3, T5} The 3 combinations these sets have in common, A intersect B: A n B= {H1. H3, H5} There are 12 possible combinations and 6 of those include a heads on the coin. This is 6/12. There are 12 possible combinations and 6 of those include an odd on the die. This is 6/12. There are 12 possible combinations and 3 of those include both an odd on the die, and a heads on the coin. This is 3/12. 6/12 + 6/12 - 3/12 = 9/12 Simplify the above number to 3/4, which is the correct answer to this question. If you draw a Venn diagram, you will see that the set consisting of tails and evens {T2, T4, T6} falls outside the circles. The diagram makes it easy to see that 9 of the 12 possible combinations fall inside the circle, and 3 of the 12 fall outside. Hope this helps someone. I solidified the information for myself by writing it!
How many possible combinations of three letters are there?
Say you have the letters A,B, and C. Here are all the possible combinations. * ABC * ACB * BAC * BCA * CAB * CBA So, 6 if you don't repeat any of the letters. If you DO repeat letters, then simply take the number of letters you have, (3 for instance), and multiply it to the power of the number of letters you have. So, for 3 letters, the formula would be 33 . Or if you had 4 letters it would be 44 and so on.
How many combinations of coins in 3?
If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7. If the coins are a,b,and c, the combinations are a, b, c, ab, ac, bc, abc. If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.
Carbon forms how many bonds?
Four bonds. It can form double and triple bonds, possible combinations that a carbon atom can have are, (a) 4 single bonds, (b) 1 double and (c)2 single, 1 triple and 1 single
What is meant by 'scrambling of allelic combinations?
Recombination, or crossing over, is the exchanging of DNA between homologous chromosomes at meiosis. It results in novel combinations of alleles in the gametes, that is, it scrambles the alleles into new combinations, Let's take an example of an individual that has genes A,B and C on one chromsome, and has the alleles a and c on the other chromosome of the pair: A---B---C a---B---c If crossing over occurs between the genes A and B (and not between B and C), then we can get the following genotypes in the gametes, in addition to the above two combinations: : A---B---c a---B---C Crossing over has scrambled the allelic combinations and given us two new additional ones in the gametes. If we allow recombination between B and C, then even more combinations are possible. One can easily see how recombination can add enormous amounts of genetic variation into a population. Also, note that if no recombination occurs, only the two original combinations of alleles will make it into the gametes.
How many different hands of poker can you make with 7 cards?
There are 20 unique 5-card hands. Solution: First break apart the player card combinations. You can either use player card 1, player card 2, or both player cards 1 and 2 with the hand. Therefore, you are taking 5 cards, 3 at a time, when playing with both player cards, and 5 cards, 4 at a time, when playing with 1 player card. Mathematically, this can be expressed using the Binomial coefficient 2 x ( 5 choose 4 ) + ( 5 choose 3 ) = Number of possible 5-card hands. 5 choose 4 = 5 : This represents the combinations between 1 player card and 5 table cards, 4 at a time. (http://www.wolframalpha.com/input/?i=5+choose+4) 5 choose 3 = 10 : This represents the combinations between 2 player cards, and 5 table cards, 3 at a time. (http://www.wolframalpha.com/input/?i=5+choose+3) Thus, 2 x ( 5 ) + ( 10 ) = 20 . Further Information: All possible hand combinations are listed below. A and B are the two player cards. 0 through 5 are the five table cards. ----- A 1 2 3 4 A 2 3 4 5 A 3 4 5 1 A 4 5 1 2 A 5 1 2 3 B 1 2 3 4 B 2 3 4 5 B 3 4 5 1 B 4 5 1 2 B 5 1 2 3 A B 2 3 4 A B 3 4 5 A B 1 2 3 A B 4 5 1 A B 5 1 2 A B 4 5 2 A B 4 1 2 A B 5 1 3 A B 5 2 3 A B 1 3 5
What are two combinations of numbers that add to 15?
There are infinitely many possible solutions. Select ANY number, A, greater than 7.5 and let B = 15 - A Then B is different from A and A + B = A + 15 - A = 15 Since there are infinitely many possible values for A, there are infinitely many solutions.
What is the following word letters are all one off- like a or c instead of b word bboxno?
In a permutation problem such as this, there are six spaces, each of which could be one of two letters. This means there are sixty-four possible combinations. The two obvious combinations are aanwmn and ccpyop. Looking at those, the word is then canyon.
