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In my opinion? 1: Foo Fighters 2: Dire Straits 3: Rush
"Stick Click"
I think you keep hitting it...
Between 2 and 5 women get pregnant after a csection and tubal.
The odds of hitting 2 straights in a row at 5 card stud is about 5%. Since the deck is reshuffled between deals, the two hands are sequentially unrelated, so the odds of two deals with two straights is simply th odds of one times the odds of another. In order to draw a straight, you need to draw an ace, 2, 3, 4, 5, or a 10, jack, queen, king, ace, assuming that ace can be high or low. The odds of drawing one of these cards is 10 in 13, but you have 5 chances to do so, so the odds of drawing the first card is 50 in 13. The odds of drawing the second card is 39 in 51, but you have 4 chances to do so, so the odds of drawing the second card is 156 in 51. Similarly, the odds of drawing the third, fourth, and fifith card is 38 in 50, 37 in 49, and 36 in 48. Multiply these odds and you get 19,740,240 in 77,968,800. Reducing that to lowest terms, you get 246,753 in 1,112,110, which is the odds of drawing a straight. The numeric value of the odds is 0.22187823146990855221156180593646, or about 22% Square that and you get 60,887,043,009 in 1,236,788,652,100. That is aready in lowest terms, so that is the odds of drawing two sequential straights. The numeric value of the odds is 0.049229949600214317813758989938262, or about 5%.
The odds of getting heads on a single coin flip are 1 in 2. To find the probability of getting three heads in a row, you multiply the probability of getting heads on each flip: ( \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8} ). Thus, the odds of getting three heads in a row when flipping a coin are 1 in 8.
The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.===================================Opinion #2:-- There are 36 possible outcomes when 2 dice are rolled.-- Only one of the outcomes is a 2.-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .-- The 'odds' are 1,011 to 989 against it.
The answer I'm editing says the odds are 1 in 8. This is true only if you actually mean the probability of getting 3 tails in a row, rather than just 3 of either heads or tails in a row. In mentioned case, the first flip doesn't matter which side it lands on, just the proceeding two flips do. So, the odds of flipping a coin three times with the same outcome are 1 in 2^2 or 1 in 4. The odds of flipping three tails in a row are 1 in 2^3 or 1 in 8.
One half, 1:2, 1/2, etc...
Rolling 2 twice in a row in the first two rolls is 1/6*1/6 = 1/36. But rolling 2 twice eventually is as close to certainty as you can get.
Very poor. New York Lotto, for instance, is 6 balls in a field of 54, with two games played for a dollar. The odds of hitting the jackpot is thus 2 in 25,827,165.
There are 4 possible outcomes, HH, HT, TH, TT. If we assume the odds of tossing heads or tails on any toss is 1/2 (50:50) the odds of tossing heads twice in a row is 1/4 (or 25%).
Odds of rolling seven once (2 dice) is 1:6, twice in a row, odds are 1:36. The reason is- the first die can be any number, but the second die must be a particular number. For example, if the first die is 6, then the second die has to be 1 to make 7. When an event occurs twice, and the two events are unrelated, then you can multiply the odds together= 1/6 * 1/6 = 1/36.
I just read that the odds of shooting 2 consecutive holes in one were on the order of 1 to 10,000,000. The story was about a guy who shot 2 in a row. I believe that, on the pro circuit, Arnold Palmer was the only one to do it . . . it could have been that he shot 2 holes in one in the same round, though.
The odds of a four-child family having four boys can be calculated using the probability of each child being a boy, which is typically 1/2. Therefore, the probability of having four boys in a row is (1/2) × (1/2) × (1/2) × (1/2) = 1/16. This means the odds against having four boys are 15 to 1, as there are 15 other combinations of boys and girls possible in four children.
The odds of flipping a coin and having it come up heads three times in a row is (1/2)*(1/2)*(1/2)=(1/8) or 12.5% ■