The "g" of NaHCO3 refers to the grams of sodium bicarbonate (baking soda) in a given quantity or solution. The molar mass of NaHCO3 is approximately 84.01 g/mol, meaning one mole of sodium bicarbonate weighs about 84.01 grams. Depending on the context, "g" can also indicate the amount needed for a specific reaction or application.
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Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
NaHCO3 ----> H2O Mass 2.10g 0.045g RAM 84 g/moles 18 g/moles number of moles 0.025moles 0.025moles
To find the moles of NaHCO3 in a 3.00 g sample, first calculate the molar mass of NaHCO3 (84.01 g/mol). Then, divide the mass of the sample by the molar mass to obtain the moles of NaHCO3. For this sample, 3.00 g / 84.01 g/mol ≈ 0.036 moles of NaHCO3 are present.
There are 0.47 grams of oxygen in 0.53 grams of NaHCO3.
The balanced chemical equation for the breakdown of sodium bicarbonate (NaHCO3) is: 2 NaHCO3 -> Na2CO3 + CO2 + H2O From this equation, it can be seen that one mole of NaHCO3 produces one mole of H2O. The molar mass of NaHCO3 is 84 g/mol. Therefore, 168 g of NaHCO3 will produce 84 g of H2O.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
Sodium Bicarbonate = NaHCO3 Molecular weight = Summation of individual molecular weights of elements =[(1)(22.99 g/mol) ] + [(1)(1.01 g/mol)] + [(1)(12.01 g/mol)] + [(3)(15.99 g/mol)] =84.01 g/molSo,(86.6 g) / (84.01 g/mol) = 1.031 mol
1 mole of NaHCO3 Na = 1 * 22.99 g = 22.99 g H = 1 * 1.01 g = 1.01 g C = 1 * 12.01 g = 12.01 g O = 3 * 16.00 g = 48.00 g Total = 84.01 g There are 84.01 grams in one mole of NaHCO3.
honestly i am using this to pass my exams so plz send accurate awns ..... (⓿_⓿):P
The answer to the conversion is that 35.0 grams of hydrochloride (HCL) equals 0.76 moles. The conversion rate is 35.0 grams divided by 46 gram per mole. A mole is the molecular weight of a substance.
Sodium Bicarbonate come from absorption of CO2 into NaOH Total reaction is 2NaOH + CO2 -> NaHCO3 + H2O Each mole of NaHCO3 come from absorption of 1 mole CO2 Molecular weight of NaHCO3 is 84 g/mol and CO2 is 44 g/mol It is that 84 g of NaHCO3 had 44 g of CO2 By weight ratio it is 52% CO2 in Sodium Bicarbonate.
All you need is the moles and the mass of NaHCO3 and you have the moles 0.025 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 2.1 grams of sodium bicarbonate ---------------------------------------------