The process of a radioactive decay is atomic nucleus of an unstable atom loses energy by emitting ionizing particles
Alpha
Nothing, it is purely a random quantum mechanical process.But there are many ways to measure it. Once you can measure it though the results can be used in many ways including making very accurate estimates of the ages of bodies that died thousands of years ago, fossils, rocks, etc.
The equation for the beta decay of 32P: 1532P --> 1632S + -10e where the e is a beta particle, represented as an electron. The daughter atom is sulfur and has an atomic number of 16.
The reason why an atomic bomb produces such a large explosion is that certain radioactive isotopes, such as U-235 or plutonium, can be made to undergo a chain reaction in which all the atoms will decay in a very short period of time (a small fraction of a second) releasing all the energy at once. Radium does not do that. However, if you had a substantial quantity of radium you could certainly use it to create radioactive contamination which could induce cancer in many people. That is known as a "dirty bomb".
The daughter isotope of Pu-239 is U-235.
Alpha
The decay equation for uranium-238 (U-238) decaying into an alpha particle (helium-4) can be represented as follows: (^{238}{92}\text{U} \rightarrow ^{4}{2}\text{He} + ^{234}_{90}\text{Th}). This equation shows the radioactive decay process of U-238 into an alpha particle and thorium-234.
alpha
Uranium 238 breaks down into a series of radioactive products formed by giving off radiation. Uranium-238, Thorium-234, Protactinium-234, and Uranium-234 are the first 4 in the series.
Because all the particles formed are radioactive.
See the links below.
Uranium 238 goes through a decay series until it becomes lead. An intermediate product of this decay series is Thorium 234. Uranium 238 decays into an atom of Thorium 234 and an atom of Helium 4. The Helium 4, being a gas, frequently escapes into the atmosphere. Since the decay of Uranium 238 into Thorium 234 and Helium 4 gives off heat and mass, nature does not normally reverse the process.
The decay chain for U-238 stops at lead because lead-206 is a stable isotope, meaning it does not undergo further radioactive decay. Once uranium-238 undergoes a series of alpha and beta decays, it eventually reaches a stable isotope of lead, which ends the decay chain.
What is missing is the type of decay that occurs during the transformation. For example, uranium-238 decays into thorium-234 through alpha decay, so the missing component would be the emission of an alpha particle in the balanced equation.
No, uranium-235 (U-235) is not stable. It is a radioactive isotope that undergoes radioactive decay, emitting particles and energy in the process.
I'm not sure if there is one word to describe different processes. Thus there can be radioactive decay into a different isotope (alpha or beta decay), gamma ray emission which means a change in energy state of the nucleus, nuclear fission as in U-235 in a reactor, and neutron induced change such as U-238 absorbing a neutron becoming Pu-239.
Thorium-234 does not change into Uranium-234. Thorium-234 undergoes radioactive decay to form Protactinium-234, which then decays to form Uranium-234. This process happens over multiple steps through alpha and beta decay mechanisms.