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Without the actual schematic of the device to examine any answers given would be worthless random speculation. All component values and their exact connections must be known to analyze an electronic circuit correctly and if it contains any custom ICs even that is useless as it is unlikely that the function and operation of the ICs can be determined.

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Q: What is the use of 100uF and 10uF capacitors in clap switch and the uses of the transistors the source is 6 volts?
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How capacitors are tested?

first you need a analog multimeter. put in your meter in the ohm section x10. then remove the cap in the ckt and discharge that. then connect the multimeter -ve probe to the cap +ve terminal and connect the other terminals.the needle comes to low value then com to infinity, remove the probs then connect multimeters -ve prob to the cap -ve terminal that time look carefully the meter's needle comes to the one value and go back to the infinity that the low value is capacitors equivalent resistance value. the cap is 1000uf the equivalent resistance value is around 15 at x10 .the cap is 100uf the equivalent resistance value is around 15 at x100


Can you replace a 47UF 160v capacitor on your tv with a 100UF 160V?

That depends what circuit it is in. If it is in a sweep circuit (vertical/horizontal) no because it will change the frequency of the circuit. If it is in a power supply circuit, probably yes becuase it is probable only being used as a filter. BUT if that leg of the power circuit supplies a sweep circuit, no.


How do you calculate the value of two capacitors conected together?

If the internal capacitors are separate, I mean that there are 4 terminals, a separate positive and negative for each internal cap then you can connect them in two ways. If you connect them in parallel (positive to positive and negative to negative) you just add the values together, so if each is 100UF they total 200Uf and the voltage you can apply is whatever is rated on the body. If you want to increase the voltage so you can apply higher voltage you connect them in series, one of the negatives connects to the others positive and the remaining inputs are connected to the circuit (and if each is equal in value) you divide by two so they would only be 50UF in capacitance but the total voltage you can apply is double the rated level on the body. If the caps are of different values it gets more complicated, you have to calculate the C total buy using the following formula: 1/C total = 1/C1 + 1/C2. Then the voltage dropped across each cap is proportional to the values you calculated above. Remember, the total voltage will be dropped across the caps proportionally so if the caps are rated at 50V for example and they are not equal values, you can't connect them up to 100V because the larger of the caps will have more than 50V across it because of the mis-matched value of each.


Can you replace a 25v 500uf capacitor with 25v 470uf capacitor?

It will depend on the application. If you are trying to rapair some thing which as per design needs 470uF capacitor but you only have 100uF capacitors available., you can put 5 of these in parallel if possible (if SMD you can put one on top of another and solder). That will give you a total of 500uF close to the original value. - Neeraj Sharma


Can i replace a 1000uf 10v capacitor with a 1000uf 25v capacitor?

in a psu a general yes but the peek load with go up on the diodes before it you could go for a 47uF and the peek load with go down but you might get some hum.. if it is the start up cct from a switch mode and the thing starts with a 100uF or a 47uF then fine.. you can get 68uF 50V caps from some suppliers. and in any case the tolerances on these caps is + or - 20% ish anyway.. hope this helps.. Simple answer,,,Yes, you can.


How Do you Convert 15v DC to 5v DC?

There are several ways. the most simplest is by using a single rectifying diode that only lets current pass in one direction. This is called a half wave rectifying circuit. You only get half the power also. The second is by a full wave, or bridge rectifier which consists of 4 rectifying diodes which can usually be bought as a single package with 4 pins which are identified for correct connection. This allows the alternating cycle current to pass alternatively to the output pins in a push-push mode and maintains most of the current flow that you put into it. The result is a very jerky or spikey DC current usually higher than the rated AC voltage. To smooth the spikes, extra circuitry is needed such as capacitors and maybe some smoothing coils but is way too detailed and varied for printing here. Type in your browser "Rectifier Circuits" and you will find a smorgasborg of results where some will give a more comprehensive explanation of how AC is converted to DC. Regards


How do you convert farad to ampere?

A farad is a unit of measure of capacitance. A capacitor of C farads charged up to V volts has charge of Q = CV (measured in coulombs). But this is still not power. If the capacitor is then completely discharged in say two seconds half of the power is provided than if it is discharged twice as fast (in one second). This is current. That is I = C dV/dT (amperes). dV or delta V = V if it is completely discharged. dV = 0.7*V if it is discharged to 0.3*V for example. Power is the current multiplied by the voltage (watts). So if the capacitor is completely discharged in T amount of time the power delivered is P = C * V * V / T. Or if the capacitor is charged up from zero charge to V volts in time T then the formula above is the P consumed to charge up the capacitor of C farads. You can think of capacitance as volume as in liters, cubic centimeters, or gallons. Using this analogy current would be flow rate such as gallons per minute, cc's per minute, or liters per second. I am not positive on this but I think voltage in this analogy could be thought of as pressure such as psi or bars. So power would be something like gpm * psi. In this analogy you are asking how do you convert gallons to a usable unit of power.