(300,000,000 meters per second) / (750,000 waves per second) = 400 meters per wave
Wavelength = (speed) divided by (frequency) =300,000,000 meters per second / 820,000 = 365.6 meters (rounded)-- 1,199.5 feet (rounded)-- 0.227 mile (rounded)
372.48 nano joule
107.1 MHz has higher energy photons. The photon energy increases directly proportional to frequency. However if the station operating on 90.5 MHz transmitter's power is 1.184 times or higher than that of the station operating on 107.1 MHz transmitter's power, then the 90.5 MHz signal will have higher energy because the additional photons makeup the difference. The total energy in electromagnetic radiation is the product of the energy per photon and the number of photons (i.e. amplitude of the wave) in the radiation.
The smaller the wavelength (high frequency), the higher the energy. So gamma has the highest energy, followed by x-rays, UV, visible, infrared, microwaves, radio, in descending order. This is also why green laser-pointers are more expensive than red ones ;)
Richard Schlegel - Photon Clock Theory .
680 KHz: λ (wavelength) = about 0.2739 miles and photon energy is 2.8122488E-09 electron volts.
Wavelength = (speed) divided by (frequency) =300,000,000 meters per second / 820,000 = 365.6 meters (rounded)-- 1,199.5 feet (rounded)-- 0.227 mile (rounded)
372.48 nano joule
The energy of a photon is inversely proportional to its wavelength. This means that as the wavelength increases, the energy of the photon decreases. Conversely, as the wavelength decreases, the energy of the photon increases.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
As the wavelength of a photon increases, its frequency decreases. This means the energy of the photon decreases as well, since photon energy is inversely proportional to its wavelength.
To find the wavelength of the photon, you can use the formula: wavelength = (Planck's constant) / (photon energy). Substituting the values, the wavelength is approximately 1.024 x 10^-7 meters.
The total energy of a photon with a wavelength of 3000 A is divided into two photons, one red photon with a wavelength of 7600 A, and another photon with a shorter wavelength. To calculate the wavelength of the second photon, you can use the conservation of energy principle, where the sum of the energies of the two new photons is equal to the energy of the original photon. This will give you the wavelength of the other photon.
The wavelength of a photon can be calculated using the equation: wavelength = Planck's constant / photon energy. Given the photon energy, you can plug in the values to find the corresponding wavelength.
To find the wavelength of a photon, you can use the equation c / f, where is the wavelength, c is the speed of light (approximately 3.00 x 108 m/s), and f is the frequency of the photon. Simply divide the speed of light by the frequency of the photon to calculate its wavelength.
Yes, a photon with a wavelength of 420nm contains more energy than a photon with a wavelength of 790nm. This is because energy is inversely proportional to wavelength, meaning shorter wavelengths have higher energy.
The frequency of a photon can be calculated using the equation: frequency = speed of light / wavelength. Plugging in the values for speed of light and wavelength, the frequency of a photon with a wavelength of 565nm is approximately 5.31 x 10^14 Hz.