The answer is: The momentum (mv) after the collision is the same as
the momentum before it. The rest is just arithmetic.
Before the collision, the momentum of the bullet is mv=(0.01)x(400) = 4 kg-m/sec.
After the collision, the combined mass of the wood block plus the bullet is 910 gm.
Its momentum mv=(0.910)x(v) = 4 kgm-m/sec.
v = 4/0.910 = 4.396 m/sec .
I've ignored the momentum lost during the embedding due to crunching and splintering,
both because I don't know anything about the properties of the wood, and also because
I wouldn't know what to do with them.
Since momentum is conserved in this system, the initial momentum of the rifle and bullet is equal to the final momentum of the rifle. You can find the recoil velocity of the rifle by setting up the equation: (2 kg) * V = (0.01 kg * 200 m/s). Solve for V to find the recoil velocity of the rifle.
Before the shot, total momentum of the rifle/bullet system is zero. Momentum is conserved, so must total zero after the shot. Magnitude of momentum = m V (mass, speed); we'll take care of direction independently. Momentum of the rifle: m V = (3.8) x (2.4) = 9.12 kg-m/sec backwards. We need momentum of the bullet = 9.12 kg-m/sec forward m V = 9.12 ===> V = ( 9.12 / m ) = ( 9.12 / 0.013 ) = 701.54 m/s forward
50 g = 0.05 kgF = m AA = F/m = 4000/0.05 = 80,000 meters per second2If the bullet starts from rest and no other forces act on it, thenSpeed = (acceleration) x (time) = (80,000) x (0.01) = 800 meters per second
Gravity has an effect the instant the bullet leaves the barrel. The bullet starts to fall towards the earth at the same rate as the dropped bullet. However, (assuming the ground follows the curve of the earth, or you are shooting over water) the dropped bullet will hit the ground/water first. The reason is that the as the fired bullet falls the ground is receding away from it (the curve of the earth). The extreme example of this is: the bullet is fired fast enough that as it falls, the curve of the earth is 'falling' continuously away below it; we would say this bullet is now in orbit around the planet. However, if the ground you are shooting over is 'flat' (i.e. flat like a ruler, NOT following the curve of the earth) then: yes, the two bullets will hit the ground at the same time.
the conversion of momentum law states that the total momentum of twos systems must be equal therefore M1V1 = M2V2 i am assuming the mass of the bullet is 0.0050 kg and not 50kg so (0.0050 * 250) = ( 9 * X) X = (1.25 / 9) X = 0.139 You can't answer these kind of questions with so few parameters. The bullet diameter, barrel length, powder burn rate all greatly effect the answer. The recoil is caused mainly by the gas exiting the barrel, hence muzzle brakes work.
With a Bullet - 2008 SUSPENDED was released on: USA: 2008
The recoil velocity of a gun can be calculated using the principle of conservation of momentum. The formula to calculate the recoil velocity is: Recoil velocity = (mass of bullet * velocity of bullet) / mass of gun. This formula takes into account the mass of the bullet, the velocity of the bullet, and the mass of the gun.
Muzzle velocity is the velocity of a bullet as it leaves the firearm's barrel, while recoil velocity is the backward momentum that the firearm experiences when the bullet is fired. Muzzle velocity determines the bullet's speed and trajectory, while recoil velocity affects the shooter's ability to control the firearm during and after firing.
Bullet trajectory is the path the bullet travels once it leaves the barrel. Bullets travel on a long arch and cross the line of sight twice. Once shortly after leaving the barrel and once again on target assuming the sights are properly zeroed. This is the trajectory of the bullet. Bullet velocity is the speed at which the bullet is traveling along it's trajectory.
Momentum = mass x velocity A bullet has a high momentum because its velocity is really high.
The terminal velocity of a bullet is the maximum speed it can reach when falling through the air. This speed varies depending on the size and weight of the bullet. When a bullet reaches its terminal velocity, it will no longer accelerate and will fall at a constant speed. The terminal velocity of a bullet can affect its trajectory and impact force in several ways. A higher terminal velocity means the bullet will hit the target with more force, potentially causing more damage. Additionally, the trajectory of the bullet may be affected by air resistance at higher speeds, causing it to deviate from its intended path. Overall, the terminal velocity of a bullet plays a significant role in determining its impact on a target.
To reduce the velocity of a bullet in air, you can increase the drag force acting on the bullet by using a heavier or more aerodynamically shaped bullet, or by increasing the air density (e.g., shooting at higher altitudes). Additionally, you can decrease the initial muzzle velocity of the bullet by using a lower-powered cartridge or firearm.
It depends on the thickness of the glass and the muzzle energy of the bullet, not just the velocity.
The force exerted on the bullet and the recoil force against the rifleman, are equal to each other (for every action there is an equal and opposite reaction). The bullet has a very small mass, and the rifle/rifleman possess a large mass, force is equal to one half mass times velocity squared, F=m/2*v^2. So velocity of the bullet is the square root of twice force divided by mass, small mass equals large velocity. Another way of looking at this problem is to invoke the law of the conservation of momentum: mass(bullet)*muzzle_velocity(bullet) = mass(rifle)*recoil_velocity(rifle). This is an approximation that neglects the momentum carried away the propellant (both spent and unburned) that exits the muzzle after the bullet.
Yes, the bullet fired from a recoiling rifle typically has a greater velocity compared to the rifle itself.
The momentum of a bullet fired from a gun is the product of its mass and velocity. It is a vector quantity that represents the motion of the bullet in a specific direction and is conserved in the absence of external forces.
"The velocity of the bullet was 300 metres per second."