A half life pertains to the time it takes for exactly half of a substance to disappear. So, if U235 has a half life of 700 million years, it will take 700 million years for half of it to decay. That would leave .5kg or 500g.
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
When food is burned, the mass of the food remains constant. However, the chemical bonds in the food molecules break, releasing energy in the form of heat and light. The ash residue that remains after burning is a fraction of the original mass and consists of the non-combustible components of the food.
The half-life on 222Rn86 is 3.8235 days. A sample of this isotope will decay to 0.8533 of its original mass after 21 hours. AT = A0 2(-T/H) AT = (1) 2(-21/(24*3.8235)) AT = 0.8533
One-half of the original amount. That's precisely the definition of "half-life".
If a radioisotope undergoes six half-lives, only (1/64) or (0.015625) of the original radioisotope remains, because half of the remaining material decays at each half-life.
1/8 of the original amount remains.
One eighth remains.
A quarter remains.
2
Approximately 25% of the Earth's original amount of 40K remains today, given that one half-life of 40K is 1.26 billion years. This means that half of the original amount decayed in 1.26 billion years, leaving behind the remaining 50%, which is now further decaying to reach 25% after 4.5 billion years.
The halflife of 235U is 704 million years. 1420 million years is approximately two halflives, so about 24.7% would be remaining.
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
The rock would be approximately 1.51 billion years old. This estimation is based on the known half-life of uranium-238, which is about 4.5 billion years. By determining that 55 percent of the original uranium-238 remains, you can infer the age of the rock by calculating how many half-lives have passed.
It remains an improper fraction.
When you divide both the numerator and denominator of a fraction by the same non-zero number, the value of the fraction remains unchanged. This is because you are essentially scaling both parts of the fraction equally, which does not affect its overall ratio. For example, if you have the fraction ( \frac{a}{b} ) and you divide both by ( c ) (where ( c \neq 0 )), the fraction simplifies to ( \frac{a/c}{b/c} ), which is equivalent to the original fraction.
An eighth remains.
Yes, it is false that dinosaur footprints are original remains.