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The half-life on 222Rn86 is 3.8235 days. A sample of this isotope will decay to 0.8533 of its original mass after 21 hours.

AT = A0 2(-T/H)

AT = (1) 2(-21/(24*3.8235))

AT = 0.8533

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Q: The half life of Rn-222 is 4 daysWhat was the original mass of a sample of this isotope remains after 21 hrs?
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