Two aluminum atoms and three sulfur atoms are combined in the compound aluminum sulfide (2 Al + 3 S = Al2S3).
1s2, 2s2 2p6, 3s2 3p1or[Ne], 3s2 3p1
The ground state electronic configuration of aluminum is [Ne] 3s2 3p1.
In the electron configuration of aluminum, the 3p1 electron corresponds to the 3rd energy level (n=3) and is in the p subshell. The second quantum number, also known as the azimuthal quantum number (l), for a p subshell is 1. Therefore, the second quantum number of the 3p1 electron in aluminum is l = 1.
The stable ion of aluminum is Al 3+, which means it has three fewer electrons. The aluminum atom has shed its outer shell of 3s2 3p1 and has an electron configuration equal to that of Neon, or 1s2 2s2 2p6.
[Ne] 3s2 3p1
For aluminium the ending is 3p1 and for sulfur is 3p4.
(Ne) 3S2 3P1
Type your answer here... nElectron Configuration: [ Ne]3s2 3p1
Type your answer here... nElectron Configuration: [ Ne]3s2 3p1
The electron configuration of aluminum is 1s2 2s2 2p6 3s2 3p1. This means aluminum has 13 electrons in total, with two in the first energy level, eight in the second energy level, and three in the third energy level.
[Ne] 3s2 3p1
There is no such thing as AI in chemistry. Al (with a lowercase L) is aluminum. It has the electron configuration 1s2 2s2 2p6 3s2 3p1
The 3p1 electron configuration belongs to phosphorus with the electron configuration 1s2 2s2 2p6 3s2 3p1. This means that phosphorus has 15 electrons, with the last electron occupying the 3p subshell.
1s2, 2s2 2p6, 3s2 3p1or[Ne], 3s2 3p1
The electron configuration of aluminum in the excited state is 1s2 2s2 2p6 3s2 3p1. In its ground state, aluminum has an electron configuration of 1s2 2s2 2p6 3s2 3p1. By exciting an electron to a higher energy level, such as from 3p1 to 3s1, the electron configuration changes in the excited state.
The ground state electronic configuration of aluminum is [Ne] 3s2 3p1.
In the electron configuration of aluminum, the 3p1 electron corresponds to the 3rd energy level (n=3) and is in the p subshell. The second quantum number, also known as the azimuthal quantum number (l), for a p subshell is 1. Therefore, the second quantum number of the 3p1 electron in aluminum is l = 1.