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Work = (force) x (distance) = 7 x 2.4 = 16.8 joules

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15y ago

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An object with a mass of 21 kilograms is lifted through a distance of 7 meters How much?

question 24 on penn foster is C.


How much work is done when 700 n object is lifted straight up a distance of 4 meters?

700 x 4 = 2,800 newton-meters = 2,800 joules


An object with a mass of 21kilograms is lifted through a distance of 7 meters How much work is done?

use the formula W = mgs W stands for work done in joules m stands for mass of the object g stands for gravity s stands for the distance the object is lifted W = mgs W = 78kilograms•9.8m/s2•6meters W = 4586.4 J (joules) answer would be 4,586.4 J


How much work is done when an object with a mass of 78 kilograms is lifted through a height of 6 meters?

78*6*9.8 N = 4586.4 N


What object do you measure in meters?

Length or distance is measured in meters.


An object of mass 4.5 is lifted through a distance of 10m H ow much work is done?

I believe that when you say 'lifted through', you mean lifted to a height of 10m. If so, the amount of work is such: Work= Force x Distance which have the units (Joules = Newtons x meters) When the object is lifted, it increases in its potential energy. The equation for this is: Potential energy = mass x gravitational force x height = 4.5 x 9.81 x 10 =441.45 Joules As 1 joule = 1 newton x meters and we have 441.45 Joules, 441.45 joules of works is done! :D


A 10kg object is lifted up to 10 meters How much potential energy has the object gained?

The potential energy gained by the object is 1,000 Joules. Potential energy is calculated using the formula PE = mgh, where m is the mass of the object (10 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height the object is lifted (10 meters).


How do you get joules with only distance and weight?

To calculate the amount of energy (joules) required to lift an object, you can use the formula: Energy (joules) = Weight (Newtons) x Distance (meters) x gravitational constant (9.81 m/s^2). Simply multiply the weight of the object by the distance it is lifted and the value of gravity to determine the total energy in joules.


Lever effect for lifting?

The lever effect for lifting refers to using a lever to reduce the amount of force needed to lift a heavy object. By increasing the distance between the pivot point (fulcrum) and the object being lifted, less force is required to lift the object. This principle is based on the relationship between the distance from the fulcrum to the applied force (effort) and the distance from the fulcrum to the object being lifted (load).


How much work would you do if you applied a 200 Newtons to an object and moved it 0 meters?

If an object does not move, no work is performed. Work is performed by a force acting through a distance.


By the time you have lifted the object 5m off the ground how much rope have you pulled through the pully?

If you have lifted the object 5m off the ground, you would have pulled 10m of rope through the pulley system. This is because as the object gets lifted, the rope length on both sides of the pulley decreases by the same amount.


What class lever is your arm?

Arm is the example of 2nd class lever.