No.
There are no lone pairs in the nitrate ion (NO3-). The nitrogen atom forms three sigma bonds with oxygen atoms, leaving no non-bonding pairs of electrons.
I am guessing you mean how many. NH3 contains 3 sigma bonds. There is no other type of sigma bonds.
linear
Phosphine (PH₃) has one covalent pair formed between the phosphorus atom and each of the three hydrogen atoms, resulting in three covalent bonds. Additionally, phosphorus has one lone pair of electrons that is not involved in bonding. Therefore, phosphine has three covalent pairs and one lone pair.
Germanium (Ge) has four valence electrons and can form four bonds by sharing these electrons. In its most common oxidation state, +4, germanium typically forms four covalent bonds with other atoms, resulting in no lone pairs. However, in certain compounds or coordination complexes, it can exhibit lone pairs depending on its hybridization and bonding environment.
To find the hybridization of an atom, you can use the formula: hybridization number of sigma bonds number of lone pairs on the atom. Count the sigma bonds and lone pairs, then determine the hybridization based on the total.
To determine the sp hybridization of a molecule, you can look at the number of sigma bonds and lone pairs around the central atom. If there are two sigma bonds and no lone pairs, the central atom is sp hybridized.
15 sigma 3 pi 10 lone pairs
To determine the hybridization of a central atom in a molecule, you can use the formula: hybridization number of sigma bonds number of lone pairs on the central atom. Count the sigma bonds and lone pairs, then use this formula to find the hybridization.
There are no lone pairs in the nitrate ion (NO3-). The nitrogen atom forms three sigma bonds with oxygen atoms, leaving no non-bonding pairs of electrons.
To determine the number of hybrid orbitals in a molecule, you can use the formula: number of hybrid orbitals number of sigma bonds number of lone pairs on the central atom. Count the sigma bonds and lone pairs to find the total number of hybrid orbitals.
To determine the hybridization of the central atom in a molecule, you can use the formula: hybridization number of sigma bonds number of lone pairs on the central atom. Count the number of sigma bonds and lone pairs around the central atom, then use this formula to find the hybridization.
To determine the hybridization of the central atom in a molecule, you can use the formula: hybridization number of sigma bonds number of lone pairs on the central atom. Count the number of sigma bonds and lone pairs around the central atom, then use this formula to find the hybridization.
two bonds and eight lone pairs
Boron typically forms three bonds and has no lone pairs due to its electron configuration.
Germanium typically forms four covalent bonds and has no lone pairs in its ground state.
In the case of carbon (C), it typically forms 4 bonds and has 0 lone pairs.