No.
There are no lone pairs in the nitrate ion (NO3-). The nitrogen atom forms three sigma bonds with oxygen atoms, leaving no non-bonding pairs of electrons.
I am guessing you mean how many. NH3 contains 3 sigma bonds. There is no other type of sigma bonds.
linear
Germanium (Ge) has four valence electrons and can form four bonds by sharing these electrons. In its most common oxidation state, +4, germanium typically forms four covalent bonds with other atoms, resulting in no lone pairs. However, in certain compounds or coordination complexes, it can exhibit lone pairs depending on its hybridization and bonding environment.
Oxygen typically has two lone pairs and forms two bonds when it is in its most common oxidation state (−2) in compounds like water (H₂O) or in diatomic oxygen (O₂). In its elemental form, O₂, each oxygen atom shares two electrons with another oxygen atom, resulting in a double bond. Thus, in O₂, each oxygen has no lone pairs, but in water, each oxygen has two lone pairs and forms two single bonds with hydrogen atoms.
To find the hybridization of an atom, you can use the formula: hybridization number of sigma bonds number of lone pairs on the atom. Count the sigma bonds and lone pairs, then determine the hybridization based on the total.
To determine the sp hybridization of a molecule, you can look at the number of sigma bonds and lone pairs around the central atom. If there are two sigma bonds and no lone pairs, the central atom is sp hybridized.
15 sigma 3 pi 10 lone pairs
To determine the hybridization of a central atom in a molecule, you can use the formula: hybridization number of sigma bonds number of lone pairs on the central atom. Count the sigma bonds and lone pairs, then use this formula to find the hybridization.
There are no lone pairs in the nitrate ion (NO3-). The nitrogen atom forms three sigma bonds with oxygen atoms, leaving no non-bonding pairs of electrons.
To determine the number of hybrid orbitals in a molecule, you can use the formula: number of hybrid orbitals number of sigma bonds number of lone pairs on the central atom. Count the sigma bonds and lone pairs to find the total number of hybrid orbitals.
To determine the hybridization of the central atom in a molecule, you can use the formula: hybridization number of sigma bonds number of lone pairs on the central atom. Count the number of sigma bonds and lone pairs around the central atom, then use this formula to find the hybridization.
To determine the hybridization of the central atom in a molecule, you can use the formula: hybridization number of sigma bonds number of lone pairs on the central atom. Count the number of sigma bonds and lone pairs around the central atom, then use this formula to find the hybridization.
two bonds and eight lone pairs
Boron typically forms three bonds and has no lone pairs due to its electron configuration.
In the case of carbon (C), it typically forms 4 bonds and has 0 lone pairs.
Germanium typically forms four covalent bonds and has no lone pairs in its ground state.