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a catalyst lowers the activation energy for both the forward and reverse reaction. however, it does not change the potential energy of the reactants or products. it also does not affect the heat of reaction (delta h)

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What parameter involved in a chemical reaction will change with the addition of a catalyst?

The rate of a chemical reaction will change in the presence of a catalyst, unless the reaction is already at equilibrium.


What effect does a catalyst have on a system equilibrium?

The correct answer is a simple one: The system is unaffected by a catalyst in a system in equilibrium.


Can a catalyst change rate of reaction equilibrium position or both?

A catalyst cannot change the equilibrium position. However, it can change its rate.


How would the equilibrium concentration of H2O be affected by adding a catalyst to the mixture?

Adding a catalyst to the mixture would not affect the equilibrium concentration of H2O. A catalyst speeds up the rate of the forward and reverse reactions equally, without changing the position of the equilibrium. This means that the equilibrium concentration of H2O would not be affected by the presence of a catalyst.


What are the factors affecting equilibrium that causes shifting?

Factors that can cause a shift in equilibrium include changes in concentration of reactants or products, changes in temperature, changes in pressure (for gases), and the addition of a catalyst. When these factors are altered, the equilibrium position will shift in order to minimize the effect of the change and restore equilibrium.


What effect does a promoter catalyst have on the position of the equilibrium?

By definition a catalyst cannot affect equilibrium because although a catalyst can speed up a chemical reaction, it cannot change the thermodynamics of it, and equilibrium is determined solely by thermodynamics. A catalyst may help a system reach equilibrium more quickly, but it will not change it. One possible way a catalyst could affect equilibrium is by introducing a catalyst that affects a different reaction involving the substrate or products of the original reaction, but this would be cheating since the system would no longer be closed.


How does the catalyst affect the Keq value of a reacti on?

A catalyst does not affect the value of the equilibrium constant (Keq) of a reaction. The presence of a catalyst increases the rate of both the forward and reverse reactions equally, allowing the system to reach equilibrium more quickly but does not change the final equilibrium composition.


If a catalyst is added to a system at equilibrium and the temperature and pressure remain constant?

The catalyst will accelerate the forward and reverse reactions equally, therefore not changing the position of the equilibrium. This results in the system reaching a new equilibrium faster but with the same concentrations of reactants and products as before the catalyst was added.


If a catalyst is added to a system at equilibrium and the temperature and pressure remain constant there will be no affect on the?

Equilibrium position. The catalyst speeds up the rate at which equilibrium is reached by lowering the activation energy for both the forward and reverse reactions equally. The concentrations of reactants and products at equilibrium remain the same.


What does a catalyst not do?

Catalysts do not change the postition of the reaction's equilibrium. Adding a catalyst will increase the rate of reaction, but it will do this by providing another pathway for the reaction to occur acros, meaning a lower activation enthalpy is needed. :)


What happens to the amount of product when you use a catalyst in equilibrium?

The yield of reaction is improved.


How do you reach equilibrium fast?

To reach equilibrium faster, you can increase the concentration of reactants, raise the temperature (if it's an endothermic reaction), decrease the volume (for gases), or use a catalyst to speed up the reaction rate. It's important to remember that altering these factors can only help reach equilibrium faster, not change the position of the equilibrium itself.