C3H6O2, which is likely to be propanoic acid or a similar compound, does not react with sodium bicarbonate (NaHCO3) because it is a weak acid and does not release sufficient protons to react with the bicarbonate. However, it can undergo saponification, a process where it reacts with a base (such as sodium hydroxide) to form the salt of the carboxylic acid and glycerol. This process is typical of esters or fatty acids, leading to the formation of soap-like compounds.
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
NaHCO3 is commonly called bicarbonate of soda or baking soda.
NaHCO3 is the chemical formula f sodium bicarbonate.Carbon is here tetravalent.
All you need is the moles and the mass of NaHCO3 and you have the moles 0.025 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 2.1 grams of sodium bicarbonate ---------------------------------------------
Sodium Bicarbonate.
When sodium bicarbonate (NaHCO3) is exposed to an acidic environment, such as vinegar or lemon juice, it undergoes a chemical reaction that releases carbon dioxide gas. This gas forms bubbles, creating the effervescence seen when NaHCO3 is mixed with an acid.
Sodium bicarbonate (NaHCO3) is not an acid; it is a salt. When dissolved in water, it undergoes hydrolysis to produce a weakly basic solution due to the presence of the bicarbonate ion. This is why NaHCO3 is often used as an antacid to neutralize excess stomach acid.
The answer is NaHCO3
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
The ratio of NaHCO3 to WHAT!
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
NaHCO3 is commonly called bicarbonate of soda or baking soda.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
The chemical formula for sodium bicarbonate is NaHCO3.
The chemical formula for sodium bicarbonate is NaHCO3.
The scientific abbreviation for sodium bicarbonate is NaHCO3.
Baking soda is sodium bicarbonate - NaHCO3.