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Calculate the velocity of a satellite moving in a stable circular orbit about the Earth at a height of 2700 km?
The answer to the question: What is the circular velocity of a satellite in meters whose orbit is 2700 km from the Earth surface?
Use Kepler's third Law
The answer is: 6623 m/s.
Formula used: (GM/d)^.5
G=6.67x10^-11m³/kg/s²
M=Mass of Earth=5.57x10^24kg
d=Distance of satellite from the Earth sea level plus radius of Earth=6378km
Bozidar kornic
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