A 100 amp service will supply your electrical current needs UP TO 100 amps.When doing load calculations on a 100 amp panel it can only be loaded up to 80 amps.
Since watts and volt-amps are different units of power, you cannot directly convert watts to volt-amps without considering the power factor of the load. In an ideal resistive circuit, 100 watts would be equivalent to 100 volt-amps. However, in practical applications with reactive components, the relationship between watts and volt-amps can vary.
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
There's more to it than just adding some larger wire. You must upgrade your meter, your weatherhead, conduit, etc. Your power company will handle the cable from the pole to your meter. After that...its up to you. 4/0 aluminum or 2/0 copper SE or USE from the meter to panel. This change has to go all the way back to the main power transformer. It's illegal to do this yourself and the power company will not turn your power back on of you do. Call an electrician.
To convert kilowatts to amps, you need to know the voltage of the circuit. The formula to calculate amps is: Amps = kilowatts / (volts * power factor). For example, if the voltage is 120V, then the amps would be 100A for a 12kW load.
A 100 amp service will supply your electrical current needs UP TO 100 amps.When doing load calculations on a 100 amp panel it can only be loaded up to 80 amps.
what is the fault in the transformer, it trips when it is charged.it is charged through the 100 amps MCCB.
Since watts and volt-amps are different units of power, you cannot directly convert watts to volt-amps without considering the power factor of the load. In an ideal resistive circuit, 100 watts would be equivalent to 100 volt-amps. However, in practical applications with reactive components, the relationship between watts and volt-amps can vary.
a 1.5 kVa source of electrical power has the capacity to supply 100 volts at 15 amps, 300 volts at 5 amps, or 1000 volts at 1.5 amps.
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
A 24 volt DC power supply provides DC amps, not AC amps. You cannot draw 1.8 amps AC from a DC power supply, without some kind of inverter stage.That is the answer to the specific wording of the question. Now the answer to the question I think was originally intended...If 1.8 amps AC is being supplied to a 24 volt DC power supply, what would the current supplied by the power supply be?Power is volts times amps, so power supplied to the power supply is 120 VAC (assumed) times 1.8 amps, or 216 watts. If the power supply is 100% efficient, then the power input equals the power output, so use the some equation to take 216 watts and divide by 24 volts, and you get 9 amps.Keep in mind, this is ideal state, assuming 100% efficiency, and no real power supply will be that.
There's more to it than just adding some larger wire. You must upgrade your meter, your weatherhead, conduit, etc. Your power company will handle the cable from the pole to your meter. After that...its up to you. 4/0 aluminum or 2/0 copper SE or USE from the meter to panel. This change has to go all the way back to the main power transformer. It's illegal to do this yourself and the power company will not turn your power back on of you do. Call an electrician.
To convert kilowatts to amps, you need to know the voltage of the circuit. The formula to calculate amps is: Amps = kilowatts / (volts * power factor). For example, if the voltage is 120V, then the amps would be 100A for a 12kW load.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
The equation for power factor is PF = True power in watts/Apparent power in Volt Amps.
A 100 amp load center typically has a maximum capacity of 100 amps for electrical circuits. It is designed to distribute power to various circuits in a building. Features may include circuit breakers, bus bars, and grounding options. The load center is an essential component of an electrical system for managing and controlling power distribution.
Given: Power P = 100 W. Reference power Po = 10^−3 W = 1 mW. Reference power level LPo = 0 dB. Get power P when entering power level LP: P = Po×10^(LI/10) W = 10^−3×10^(LP/10) W. Get power level LI in dB when entering power P in W. LP = 10×log (P / Po) dB = 10×log (P / 10^−3) = 50 dB. The reference power may be different, then the power level will be different.