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87.2 grams of glucose burned in 87.2 grams oxygen what is limiting reactant?
To determine the limiting reactant, you need to compare the amounts of reactants in terms of moles. First, convert the grams of glucose and oxygen into moles using their respective molar masses. Then, calculate the moles of products that can be formed from each reactant. The reactant that produces fewer moles of product will be the limiting reactant.
What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
The molar mass of S8 is 256 g/mol. To calculate the maximum mass of S8 that can be produced, first determine the limiting reactant by converting the masses of the reactants to moles. Then, use the stoichiometry of the reaction to find the mass of S8 produced from the limiting reactant.
What is the limiting reactant of 6.5g of C3H8O and 12.3g of O2?
The reaction between Isopropyl alcohol and oxygen is 2 C3H8O + 9 O2 equals 6 CO2 + 8 H2O. So for every mole of isopropyl alcohol, 4.5 moles of oxygen are consumed. 6.5 grams of C3H8O is .108 moles and 12.3 grams of O2 is .384 moles. This means that O2 is the limiting reactant as it needs .486 moles of O2 to finish.
What is the theoretical mass of xenon tetrafluoride that should form when 130 G of xenon is reacted with 100 G of F2?
To determine the theoretical mass of xenon tetrafluoride that forms, first calculate the limiting reactant by converting the masses of xenon and fluorine to moles using their molar masses. Then, use the mole ratio from the balanced chemical equation (Xe + 2F2 -> XeF4) to find the limiting reactant. Finally, use the limiting reactant to calculate the theoretical mass of xenon tetrafluoride formed.
What mass of HgBr2 can be produced from the reaction of 10.09 g Hg and 8.02 g Br2?
First, balance the chemical equation: Hg + Br2 → HgBr2. Calculate the molar amount of each reactant using their respective molar masses. Identify the limiting reactant (the one that produces the least amount of product). Calculate the theoretical yield of HgBr2 based on the limiting reactant.
Which reactant in the reaction of sodium carbonate and calcium chloride dihydrate is the limiting reactant if 1.00 gram of each reagent is used?
To determine the limiting reactant, calculate the moles of each reactant using their molar masses. Then, use the stoichiometry of the reaction to determine which reactant will be consumed first. Whichever reactant produces the lesser amount of product will be the limiting reactant.
Which is the limiting reactant when masses of reactants are same?
You must first convert the mass of each reactant into moles of each reactant. Having the same mass does not mean that the amount of each reactant is the same, because each reactant has its own unique molar mass. Refer to the related link below for instructions on determining limiting reactants, also called limiting reagents.
What mass CuO can be formed from the reaction of 18.7 g CuS and 12.0 g of O2?
To determine the mass of CuO formed, first calculate the moles of each reactant using their molar masses. Then, determine the limiting reactant by comparing the moles of CuO that could be formed from each reactant. Finally, use the limiting reactant to calculate the mass of CuO formed based on the balanced chemical equation.
If 100 g of CuS and 56 g of O2 are available which is the limiting reactant?
To determine the limiting reactant, first calculate the moles of each reactant by dividing the given mass by their respective molar masses. Then, determine the mole ratio between CuS and O2 in the balanced chemical equation. The reactant that produces fewer moles of product based on this ratio is the limiting reactant.
Which reagent is limiting cyclopentadiene or maleic anhydride?
To determine the limiting reagent, calculate the moles of each reactant using their respective masses and molar masses. Compare the moles of each reactant to the stoichiometry of the reaction. The reagent that produces the least amount of product based on stoichiometry is the limiting reagent.
87.2 grams of glucose burned in 87.2 grams oxygen what is limiting reactant?
To determine the limiting reactant, you need to compare the amounts of reactants in terms of moles. First, convert the grams of glucose and oxygen into moles using their respective molar masses. Then, calculate the moles of products that can be formed from each reactant. The reactant that produces fewer moles of product will be the limiting reactant.
What is the limiting reactant for the reaction below given that you start with 2.50 grams C and 2.50 grams SiO2?
To determine the limiting reactant, you need to compare the amount of product that each reactant could potentially produce. Calculate the moles of each reactant using their respective molar masses, and then find the mole ratio of C to SiO2 in the balanced chemical equation. Whichever reactant produces less product is the limiting reactant.
After a chemical reaction starts when will a chemical reaction end?
When the limiting reactant is completely used up. A limiting reactant is the reactant that determines the amount of product. To determine this use the balanced chemical reaction with the masses of the reactants to determine the moles of product formed. The reactant that forms the least amount of product will be the limiting reactant.
What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
The molar mass of S8 is 256 g/mol. To calculate the maximum mass of S8 that can be produced, first determine the limiting reactant by converting the masses of the reactants to moles. Then, use the stoichiometry of the reaction to find the mass of S8 produced from the limiting reactant.
What is the limiting reactant of 6.5g of C3H8O and 12.3g of O2?
The reaction between Isopropyl alcohol and oxygen is 2 C3H8O + 9 O2 equals 6 CO2 + 8 H2O. So for every mole of isopropyl alcohol, 4.5 moles of oxygen are consumed. 6.5 grams of C3H8O is .108 moles and 12.3 grams of O2 is .384 moles. This means that O2 is the limiting reactant as it needs .486 moles of O2 to finish.
What is the theoretical mass of xenon tetrafluoride that should form when 130 G of xenon is reacted with 100 G of F2?
To determine the theoretical mass of xenon tetrafluoride that forms, first calculate the limiting reactant by converting the masses of xenon and fluorine to moles using their molar masses. Then, use the mole ratio from the balanced chemical equation (Xe + 2F2 -> XeF4) to find the limiting reactant. Finally, use the limiting reactant to calculate the theoretical mass of xenon tetrafluoride formed.
What is the theoretical yield for reaction when 10.1g Mg allowed to react with 10.6 g O2 11.9G MgO is collected Reaction 2Mg plus O2 equals 2MgO?
The first step is to determine the limiting reactant, which is the reactant that is used up first in the reaction. To do this, calculate the moles of each reactant using their molar masses. Then compare the mole ratio of the reactants to the stoichiometry of the reaction to find the limiting reactant. Once you have the limiting reactant, use its moles to calculate the theoretical yield of the product using the stoichiometry of the reaction.
