0
Well, honey, in a compound like Cl2, each chlorine atom has an oxidation number of 0 because it's a diatomic molecule. But if you're talking about when chlorine forms a compound with something else, then its oxidation number can vary depending on the compound. So, in short, in Cl2, the oxidation number of each chlorine atom is 0. Hope that clears things up for ya, darling!
What else can I help you with?
How many moles K are needed to react with 15 moles of Cl2?
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
How do you calculate the balance equation for Na plus Cl2?
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
How Many Moles Of PCl5 Can Be Produced From 58.0 G Of Cl2 (and Excess P4)?
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
What happens if Cl2 is decreased the following chemical equilibrium of C2H4 plus Cl2--Ch2H4Cl2?
If the concentration of Cl2 is decreased, the reaction will shift to the left to try to replace the lost Cl2. This means more C2H4 will react with any remaining Cl2 to form more C2H4Cl2 until a new equilibrium is reached with a lower concentration of Cl2.
In the reaction Mg plus Cl2 MgCl2 what should be the coefficient for Cl2?
1
What is the oxidation number of cl in cl2?
It is equal to zero. In pure elemental form.
What are the oxidation numbers of Cl?
-1 is most common, but Cl can exhibit oxidation numbers from -1 to +7 in its compounds.
What is the oxidation half reaction of Cl2 2Cu to 2CuCl?
Cl2 + 2Cu --> 2CuCl Oxidation reaction is Cu --> Cu+ + 1e Reduction reaction is Cl + 1e --> Cl- Redox reaction is Cu + Cl --> Cu+ + Cl-
What is the oxidation number cucl2?
Oxidation number is the charge per atom in a compound. Cl2= 2- (Cl= 1-) Cu would have to be 2+ to balance the compound, because there is only one copper atom.
What type of reaction does cl2 h2o - Hclo have?
The reaction between Cl2 and H2O to form HOCl (also written as HClO) is a redox reaction. Chlorine in Cl2 is reduced from 0 to +1 oxidation state in HOCl, while hydrogen in H2O is oxidized from +1 to +1 oxidation state in HOCl, indicating transfer of electrons.
When the equation fe plus cl2?
When iron (Fe) reacts with chlorine gas (Cl2), they form iron (III) chloride (FeCl3) according to the equation: 2 Fe + 3 Cl2 → 2 FeCl3. This reaction is a redox reaction where iron is oxidized and chlorine is reduced.
What are the oxidation numbers of copper CuCl?
Oxidation number is the charge per atom in a compound. Cl2= 2- (Cl= 1-) Cu would have to be 2+ to balance the compound, because there is only one copper atom.
What is the oxidation state for 2na plus cl2?
2Na + Cl2 -> 2NaCl. The oxidation state of the sodium ion in NaCl is +1 and the oxidation state of Chloride ion is -1. Oxidation states of the elemental reactants is zero (as for all elements)
What is the oxidation state of Cl on HClO2?
The central atom in this molecule is chlorine. It is bonded with two oxygen atoms and a hydrogen atoms. The oxidation number of chlorine is +3: four covalent bonds with oxygen yields +4 and the bond with hydrogen yields -1.
How do you balance redox H2O Cl2 P4 - POCl3 HCl?
To balance the redox reaction involving H2O, Cl2, P4, POCl3, and HCl, you need to first assign oxidation numbers to each element and then balance the atoms and charges. The balanced equation is: 4 H2O + 6 Cl2 + P4 -> 4 H3PO4 + 6 POCl3 + 4 HCl.
The following reaction takes place in an acidic solution. MnO4–(aq) + Cl–(aq) Mn2+ + Cl2(g) (unbalanced) Write the reduction and oxidation half-reactions (without electrons). :(?
Reduction Half-Reaction: MnO4-(aq) → Mn2+(aq) Oxidation Half-Reaction: Cl-(aq) → Cl2(g)
How does the oxidation state of Li change in the following reaction?
it goes from 0 to +1
