Yes this is correct when you burn it.
CuCO3 ==> CO2 + CuO (heat is the catalyst, written above the arrow)
Here are the equations for the thermal decomposition of copper carbonate (notice that a metal oxide is formed, just as it was with calcium carbonate): Copper carbonate → copper oxide + carbon dioxide CuCO3 → CuO + CO2
The correct answer is co2+c= 2co
This is not a decomposition reaction.
The correct equation for the effect of heat on CaCO3 (calcium carbonate) is: CaCO3 (s) -> CaO (s) + CO2 (g) This reaction represents the decomposition of calcium carbonate into calcium oxide and carbon dioxide upon heating.
When CuCO3 is heated, it decomposes into copper(II) oxide (CuO) and carbon dioxide (CO2) gas. This is a decomposition reaction where the solid CuCO3 breaks down into a solid and a gas when heated.
CuCO3 ---> CO2 + CuO which is copper oxide
The thermal decomposition in this case is: CuCO3 -------------CuO + CO2
CuCO3 ==> CO2 + CuO (heat is the catalyst, written above the arrow)
CuCO3 = CuO + CO2
Copper doesn't react with carbon dioxide at room temperature.
CuO + CO2 -> CuCO3 CuO is copper oxide and is an ionic bond Cu(2+) and O(2-) CuCO3 is also an ionic bond, as one oxygen from copper oxide has joined with the covalently bonded carbon dioxide, CO2, to form carbonate, a polyatomic ion. Cu(2+) and CO3(2-)
CO2 , H2O , and heat.
It can be either depending on the reaction. For example. here it is a product. 2Cu + H2O + CO2 + O2 --> Cu(OH)2 + CuCO3 it is a product. While in this reaction CuCO3 + 2HCl --> CuCl2 + CO2 + H2O it is a reactant.
Copper oxide reacts with carbon dioxide to form copper carbonate. This reaction can be represented by the chemical equation: CuO + CO2 -> CuCO3.
Get copper suphate + carbon dioxide + water + residual of the original component not in the proper proportion.
CuCO3 is copper(II) carbonate. Copper(II) carbonate decomposes at 290°C. This decomposition forms Copper(II) oxide (CuO) and carbon dioxide (CO2). CO2 and lime water (Ca(OH)2) will react to form calcium carbonate (CaCO3) and water (H2O). However, if CO2 is in excess, calcium bicarbonate Ca(HCO3)2 is formed. So, the following reactions take place:Decomposition at 290°C:CuCO3 → CuO + CO2In the test tube with lime water:Ca(OH)2 + CO2 → CaCO3 + H2OIf excess CO2 is added:CaCO3 + H2O+ CO2 --> Ca(HCO3)2