No, entropy is a state function.
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It can be + or - depending on the value of the entropy (∆S). Recall, that ∆G = ∆H - T∆S and for a spontaneous reaction, ∆G must be negative, so you can see how this will depend on the values and signs of both enthalpy and entropy.
No, heat and work are not path functions. Heat and work are energy interactions between a system and its surroundings that depend on the process taken, not just the initial and final states. Path functions are properties whose values depend on the path followed to reach that state, such as change in temperature.
It's not that entropy can't be reversed, it's that the entropy of the universe is always increasing. That means that while you can reduce the entropy of something, the entropy of another thing must go up even more so that in total, the entropy goes up.
The entropy of mixing is the change in theconfiguration entropy, an extensivethermodynamic quantity, when two differentchemical substances or components are mixed and the volume available for each substance to explore is changed. The name entropy of mixing is misleading, since it is not the intermingling of the particles that creates the entropy change, but rather the change in the available volume per particle.[1] This entropy change is positive when there is more uncertainty about thespatial locations of the different kinds ofmolecules. We assume that the mixing process has reached thermodynamic equilibrium so that the mixture is uniform and homogeneous. If the substances being mixed are initially at different temperatures and pressures, there will, of course, be an additional entropy increase in the mixed substance due to these differences being equilibrated, but if the substances being mixed are initially at the same temperature and pressure, the entropy increase will be entirely due to the entropy of mixing.The entropy of mixing may be calculated by Gibbs' Theorem which states that when two different substances mix, the entropy increase upon mixing is equal to the entropy increase that would occur if the two substances were to expand alone into the mixing volume. (In this sense, then the term "entropy of mixing" is a misnomer, since the entropy increase is not due to any "mixing" effect.) Nevertheless, the two substances must be different for the entropy of mixing to exist. This is the Gibbs paradoxwhich states that if the two substances are identical, there will be no entropy change, yet the slightest detectable difference between the two will yield a considerable entropy change, and this is just the entropy of mixing. In other words, the entropy of mixing is not a continuous function of the degree of difference between the two substances.For the mixing of two ideal gases upon removal of a dividing partition, the entropy of mixing is given by:(1)[tex]\Delta S = n1R\ln((V1+V2)/V1) + n2R\ln((V1+V2)/V2)[/tex]where is the gas constant, n1 and n2 are the number of moles of the respective gases and V1, V2 are their respective initial volumes. After the removal of the partition, each gas particle may explore a larger volume, which causes the entropy change. Note that this equation is only valid if both compartments have the same initial pressure.Note that the mixing involves no heat flow (just the irreversible process of mixing). However, the change in entropy is defined as the integral of dQ/T over the reversible path between the initial and final states. The reversible path between these two states is a quasi-static isothermal expansion. Such a path DOES involve heat flow into the gas: dQ = PdV = nRTdV/V where T is constant (dU = 0). The above equation (1) for entropy is determined by taking the integral of dQ/T over such a path.
No, entropy is not path dependent in thermodynamics.
Entropy can be found in an irreversible process, just not directly. Since entropy is a state variable, you can invent a path connecting the initial and final states that does consist of reversible processes and then compute the total equilibrium change for that path.
it depends on the entropy and enathalpy of the reaction
If you take entropy as an extensive variable then the magnitude of the entropy does depend on the number of moles. If you take entropy as an intensive variable then its magnitude it dependent on the other variables you combined it with. However sense you always deal with entropy as a change in entropy the magnitude doesn't really matter.
No, entropy does not depend on mass. Entropy is a measure of disorder in a system and is influenced by factors such as temperature, volume, and energy distribution. It is not directly related to the mass of a system.
it depends on the entropy and enathalpy of the reaction
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State functions are quantities in thermodynamics that depend only on the current state of a system, such as temperature, pressure, volume, internal energy, enthalpy, and entropy. These quantities are independent of the path taken to reach that state.
The increase in entropy will depend on the physical states of the reactants and products. If the reactants are solid and the products are gaseous, there will likely be an increase in entropy due to the increase in disorder. However, if both the reactants and products are in the same state, the change in entropy may be minimal.
State functions in thermodynamics include temperature, pressure, volume, internal energy, enthalpy, entropy, and Gibbs free energy. These functions are properties of a system that depend only on the current state of the system, not on how the system reached that state. This is in contrast to path functions, such as work and heat, which depend on the specific path taken to reach a particular state.
This is called entropy.
The entropy of liquid formic acid (HCOOH) at a specific temperature can be calculated using the third law of thermodynamics and statistical mechanics. The entropy value will depend on the molecular structure, temperature, and specific conditions of the system.