If you take entropy as an extensive variable then the magnitude of the entropy does depend on the number of moles. If you take entropy as an intensive variable then its magnitude it dependent on the other variables you combined it with. However sense you always deal with entropy as a change in entropy the magnitude doesn't really matter.
Reactions that increase the moles of gas will increase in entropy.
1) you increased the number of moles of gas 2) you increased the number of atoms or molecules 3) you go from solid to liquid, or liquid to gas really if you see disorder, or kinetic energy, or particles, increasing, you can call that an increase in entropy.
if there is an increase in the number of gas molecules , then ^S > 0
The reaction is 2NH₃(g) → N₂(g) + 3H₂(g), and since the number of moles of gas decreases from 2 moles to 4 moles, the entropy change is negative.
The products becoming more spread out.
Reactions that increase the moles of gas will increase in entropy.
1) you increased the number of moles of gas 2) you increased the number of atoms or molecules 3) you go from solid to liquid, or liquid to gas really if you see disorder, or kinetic energy, or particles, increasing, you can call that an increase in entropy.
if there is an increase in the number of gas molecules , then ^S > 0
The reaction is 2NH₃(g) → N₂(g) + 3H₂(g), and since the number of moles of gas decreases from 2 moles to 4 moles, the entropy change is negative.
To determine the change in entropy for the reaction represented by the expression ( n^{1/2} g , + , 3h^{1/2} g , \leftrightarrow , 2nh^{3/4} g ), we need to consider the number of moles of gas on each side of the equation. If the total number of gaseous moles increases in the products compared to the reactants, the entropy change will be positive, indicating an increase in disorder. Conversely, if the number of moles decreases, the entropy change will be negative. Without specific coefficients or more context, we cannot definitively conclude the sign of the entropy change.
In the reaction ( \text{CO}_g + 3\text{H}_2g \rightarrow \text{CH}_4g + \text{H}_2O_g ), entropy typically decreases because there are four moles of gas on the reactant side (1 mole of CO and 3 moles of H₂) and only two moles of gas on the product side (1 mole of CH₄ and 1 mole of H₂O). This reduction in the number of gas molecules generally leads to a decrease in disorder, resulting in lower entropy. However, the overall change in entropy would also depend on factors like temperature and the specific properties of the substances involved.
The products becoming more spread out.
The entropy change is increased in the given reaction. This is because there are more moles of gaseous products compared to the reactants, which leads to an increase in disorder or entropy in the system.
A gas typically increases the entropy much more than the increase in moles.
A mole is a defined number of atoms/molecules of an element/compound. Therefore, the number of moles of NaCHO3 will depend on the mass of NaCHO3 that you have. To calculate the number of moles in a known sample, divide the mass of the sample (in grams) by the molecular weight.
Yes, pressure is directly proportional to the number of moles in a given system, according to the ideal gas law.
The products becoming more ordered than the reactants