The products becoming more spread out.
The products becoming more ordered than the reactants
It increases
Guys watch out the question, if your question end with positive then the answer will be An endothermic reaction that decreases in entropy. If the question end with negative then its An exothermic reaction that increases in entropy--APEX hope this help
CH4(g) + H2O(g) CO(g) + 3H2(g)
The entropy INCREASES. There are more moles in the products than in the reactants.
The products becoming more ordered than the reactants
At high temperature the entropy increase.
CO(g)+3H2(g)->CH4(g)+H2O(g)
CO(g)+3H2(g)->CH4(g)+H2O(g)
To determine the final entropy change for a reaction when multiplied by a choice, you would typically apply the principle of additivity of entropy. If you multiply a reaction by a factor, the change in entropy for the overall reaction will also be multiplied by that same factor. Therefore, if you have the standard entropy change for the original reaction, you would multiply that value by the factor you used to scale the reaction to find the final entropy change for the intermediate.
It increases
Guys watch out the question, if your question end with positive then the answer will be An endothermic reaction that decreases in entropy. If the question end with negative then its An exothermic reaction that increases in entropy--APEX hope this help
To calculate the standard entropy change (ΔS°) for a reaction, you need to use the formula: [ \Delta S° = \sum S°{\text{products}} - \sum S°{\text{reactants}} ] You would sum the standard entropy values of the products and subtract the sum of the standard entropy values of the reactants. If you provide the specific reaction and the standard entropy values, I can calculate it for you.
CH4(g) + H2O(g) CO(g) + 3H2(g)
Entropy increases. In a reaction comprised of sub-reactions, some sub-reactions may show a decrease in entropy but the entire reaction will show an increase of entropy. As an example, the formation of sugar molecules by living organisms is a process that shows decrease in entropy at the expense of the loss of entropy by the sun.
The entropy INCREASES. There are more moles in the products than in the reactants.
The entropy increase in this reaction.