CO(g)+3H2(g)->CH4(g)+H2O(g)
At high temperature the entropy increase.
endothermic, increasing entropy
Decreasing temperature, decreasing concentration of reactants, increasing the activation energy required for the reaction, and introducing an inhibitor can all decrease the rate of a reaction.
Decreasing the rate of a chemical reaction would slow down the speed at which reactants are converted into products. This can be done by lowering temperature, decreasing reactant concentration, or adding inhibitors. Ultimately, the reaction will take longer to reach completion.
Actually its a bit Controversial, when we say Entropy, alot of things come into picture. So U just can't say Entropy is increasing. But in accordance with 2nd law of thermodynamics, it is true. U have to consider a particular system and its surroundings, then study its stability and Entropy.
The products becoming more ordered than the reactants
At high temperature the entropy increase.
CO(g)+3H2(g)->CH4(g)+H2O(g)
The products becoming more spread out.
It increases
CH4(g) + H2O(g) CO(g) + 3H2(g)
The entropy INCREASES. There are more moles in the products than in the reactants.
Decreasing the temperature of the system
The products becoming more spread out.
It increases; more freely moving particles.
endothermic, increasing entropy
Synthesis reactions such as dehydration synthesis. For a reaction to proceed the there must be a net decrease in the Gibbs Free Energy of the system. The Gibbs Free Energy is made up of two terms: Enthalpy or Heat Content H Entropy S For a reaction in which the entropy is increasing to proceed there would have to be a sufficient release of heat content (enthalpy) such that Change in Free Energy G would be negative, ie decrease...