CO(g)+3H2(g)->CH4(g)+H2O(g)
At high temperature the entropy increase.
To determine the final entropy change for a reaction when multiplied by a choice, you would typically apply the principle of additivity of entropy. If you multiply a reaction by a factor, the change in entropy for the overall reaction will also be multiplied by that same factor. Therefore, if you have the standard entropy change for the original reaction, you would multiply that value by the factor you used to scale the reaction to find the final entropy change for the intermediate.
To calculate the standard entropy change (ΔS°) for a reaction, you need to use the formula: [ \Delta S° = \sum S°{\text{products}} - \sum S°{\text{reactants}} ] You would sum the standard entropy values of the products and subtract the sum of the standard entropy values of the reactants. If you provide the specific reaction and the standard entropy values, I can calculate it for you.
A reaction that leads to a decrease in entropy typically involves a transition from a more disordered state to a more ordered state. For example, the formation of ice from liquid water decreases entropy, as the molecules in ice are arranged in a structured lattice. Similarly, reactions that produce a solid or a liquid from gaseous reactants can also result in lower entropy due to the reduced freedom of movement of the particles.
endothermic, increasing entropy
The products becoming more ordered than the reactants
At high temperature the entropy increase.
CO(g)+3H2(g)->CH4(g)+H2O(g)
To determine the final entropy change for a reaction when multiplied by a choice, you would typically apply the principle of additivity of entropy. If you multiply a reaction by a factor, the change in entropy for the overall reaction will also be multiplied by that same factor. Therefore, if you have the standard entropy change for the original reaction, you would multiply that value by the factor you used to scale the reaction to find the final entropy change for the intermediate.
The products becoming more spread out.
It increases
To calculate the standard entropy change (ΔS°) for a reaction, you need to use the formula: [ \Delta S° = \sum S°{\text{products}} - \sum S°{\text{reactants}} ] You would sum the standard entropy values of the products and subtract the sum of the standard entropy values of the reactants. If you provide the specific reaction and the standard entropy values, I can calculate it for you.
CH4(g) + H2O(g) CO(g) + 3H2(g)
The entropy INCREASES. There are more moles in the products than in the reactants.
Decreasing the temperature of the system
The products becoming more spread out.
A reaction that leads to a decrease in entropy typically involves a transition from a more disordered state to a more ordered state. For example, the formation of ice from liquid water decreases entropy, as the molecules in ice are arranged in a structured lattice. Similarly, reactions that produce a solid or a liquid from gaseous reactants can also result in lower entropy due to the reduced freedom of movement of the particles.