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No, cesium is an alkali metal. Metals do not react with one another.

Cesium reacts with nonmetals and acids to form salts.

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Related Questions

Do bases react vigorously with many metals?

No, Acids react with metals to form salts.


Are alkali metals found as pure elements in sea water?

Alkali metals exist only as salts.


What charge do alkali metals form when they react with a halogen?

here r the possisble answers: both atoms lose 1 electron a covalent bond forms metal gains an electron and the nonmetal loses an electron metal loses an electron and non metal gains an electron


Acids and alkali's react together to make salts and what?

Usually they react to form a slat and water.


Most salts (alkali metals)?

Li, Na, K, NH4


What are the examples of weak salts?

These salts are weak electrolytes: examples are acetates, formates etc. of alkali metals.


What groups are the very reactive elements from?

The very reactive elements are typically found in Group 1 (alkali metals) and Group 17 (halogens) of the periodic table. Alkali metals tend to react violently with water, while halogens are known for their high reactivity and tendency to form salts with metals.


What salts are soluble?

Those salts which can dissolve in water.because water is a solvent and salts are solute.


What group of elements reacts vigorously with water and halogens?

All of the alkali metals, periodic column 1 excluding hydrogen in a wide form periodic table, and all but the two lightest alkaline earth elements, periodic table column 2 excluding beryllium and magnesium, have the reactivity specified by the question.


Halogens form what when mixed with alkali metals?

The products of the reactions are ionic salts.


Which group reacts with alkali metals to from salts?

Halogens, such as chlorine, iodine or fluorine.


Does metal react with bases to produce salts?

Yes, metals can react with bases to form salts through a process called neutralization. The metal hydroxide and the base react to form a salt and water. The salt formed will depend on the specific metal and base involved in the reaction.