no it's 0.
Na = +1
O = -2
Na2O = +1(2) + (-2) = 0
NiCl2 + 2Na --> 2NaCl + Ni
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In a neutral compound, the ratio of Fe³⁺ ions to O²⁻ ions is 2:3. This is because Fe³⁺ has a +3 charge, while O²⁻ has a -2 charge. To balance the charges, two Fe³⁺ ions contribute a total charge of +6, which is balanced by three O²⁻ ions contributing a total charge of -6. Thus, the formula of the neutral compound would be Fe₂O₃.
The reaction between sodium oxide (Na2O) and carbon dioxide (CO2) is generally exothermic. When Na2O reacts with CO2, it forms sodium carbonate (Na2CO3), releasing heat during the process. This exothermic nature is typical of reactions involving the formation of stable ionic compounds from simpler oxides and gases.
This describes an ionic compound with an 8:3 ratio of electrons to cations. The cation has a charge of +3, meaning it has lost 3 electrons. The total number of electrons in the compound is 80.
The compound formed between sodium (Na) and oxygen (O) is sodium oxide (Na2O). The formula for sodium oxide is Na2O.
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
NiCl2 + 2Na --> 2NaCl + Ni
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Sodium plus oxygen react to form sodium oxide (Na2O), which is a white solid compound. The balanced chemical equation for this reaction is: 4Na + O2 → 2Na2O.
No, it is not.
The Arsenic in AsH3 typically has a plus one charge. Therefore the H must have a -1 charge to create the compound.
Na + ( a sodium ion )A cationbonds withSO4 2- ( the polyatomic ion sulfate )an anionto formNa2 SO4The ionic compound sodium sulfate
The bromide ion (Br-) has a charge of -1. In the formation of potassium bromide (KBr), the potassium ion (K+) has a charge of +1, and the bromide ion has a charge of -1 to balance the overall charge of the compound.
Two ions with a +1 charge will bond with one ion with a -2 charge to form a neutral compound. The ratio is determined by the charges on the ions, ensuring that the overall charge of the compound is balanced.
The oxidation number of Na in Na2O is +1, since sodium (Na) typically has a +1 oxidation state. The oxidation number of O in Na2O is -2, as oxygen (O) usually has a -2 oxidation state in ionic compounds.
The charges of the ions must balance out, so the ratio of ions will be 3:2 to form a neutral compound. The total positive charge from the z3 plus ion and the total negative charge from the q2- ion must cancel out to give a net charge of zero in the compound.