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How pure benzoic acid may be separated form a solution of sand and benzoic acid?
To separate benzoic acid from a solution of sand and benzoic acid, you can use solvent extraction. Benzoic acid is soluble in organic solvents like diethyl ether, while sand is not. By adding diethyl ether to the solution, the benzoic acid will dissolve in the ether, allowing you to separate it from the sand by decanting or filtration. Then, evaporate the diethyl ether to recover the pure benzoic acid.
Why can not benzoic acid be dissolved in water at room temperature?
To be soluble a solution must be capable of being dissolved in a solvent, usually water. The HCL cannot ionize into H+ with the COOH ring in the Benzoic acid. Benzoic is hydrophobic in this solution.
A mixture of camphor and benzoic acid can be easily separated by?
Benzoic acid is more soluble than camphor in ethanol. The solution can be filtrated.
Why is benzoic acid is extracted into ether then extracted into an alkali solution prior to being precipitated with strong acid in its preparation with grignard reagent?
When you're attempting to extract benzoic acid from other organic compounds, it is necessary to change its pH by adding a layer of an basic compound such as 1M NaOH so that the benzoic acid then can be separated from the organic layer within a separatory funnel. When in NaOH, the benzoic acid loses a proton and thus becomes its conjugate base (the benzoate ion). The benzoate ion is charged and thus become miscible in the aqueous layer. To extract benzoic acid (ie get it to precipitate out of solution), a strong acid such as HCl must be added to solution. After the extraction, lower the pH of the solution, and recrystalize (use ice after the recrystalization to get benzoic acid crystals to crash out).
Why is it necessary to filter the benzoic acid solution while hot?
Filtering the benzoic acid solution while hot helps to keep the compound in solution as it cools, preventing it from crystallizing and clogging the filter paper. This ensures that all impurities are removed from the solution before it solidifies.
In the laboratory a student named Georgia weighed 5.35 grams of an unknown solid mixture containing benzoic acid copper II sulfate and sand she added 15 ml of acetone to her sample which dissolved?
The benzoic acid in the mixture dissolved in the acetone because it is soluble in acetone. Copper (II) sulfate does not dissolve in acetone like benzoic acid does. The sand in the mixture does not dissolve in acetone as it is insoluble.
How pure benzoic acid may be separated form a solution of sand and benzoic acid?
To separate benzoic acid from a solution of sand and benzoic acid, you can use solvent extraction. Benzoic acid is soluble in organic solvents like diethyl ether, while sand is not. By adding diethyl ether to the solution, the benzoic acid will dissolve in the ether, allowing you to separate it from the sand by decanting or filtration. Then, evaporate the diethyl ether to recover the pure benzoic acid.
Why can not benzoic acid be dissolved in water at room temperature?
To be soluble a solution must be capable of being dissolved in a solvent, usually water. The HCL cannot ionize into H+ with the COOH ring in the Benzoic acid. Benzoic is hydrophobic in this solution.
What is the pH of sodium benzoate?
Sodium benzoate is a salt derived from benzoic acid, which is weakly acidic. The pH of a solution containing sodium benzoate would depend on the concentration of the solution, but typically it would be acidic with a pH below 7.
Is benzoic acid soluble?
Benzoic acid is soluble in water, as are all acids, by definition. An acid is a chemical which, when dissolved in water, increases the concentration of H+ ions.
Is it possible make a saturated solution of benzoic acid using methylene chloride as the solvent?
You can make a saturated solution of anything in any solvent. The question is how much will actually be dissolved in the saturated solution. A saturated solution of salt in water will obviously have a LOT of salt in it. A saturated solution of sand in water won't have any dissolved sand at all! It'll still be saturated. What you want to know is what the solubility of benzoic acid is in methylene chloride. That I don't know. One way to find out is just add a known amount of benzoic acid to the solvent and see if it dissolves. If you search the scientific literature of organic synthesis, I'm sure the solubility of benzoic acid is known in a variety of solvents, although methylene chloride isn't the most common. I found this in the MSDS (see link to the left): SOLUBILITY IN WATER: 2.9% @ 20 C SOLVENT SOLUBILITY: Soluble in alcohol, ether, benzene, chloroform,acetone, carbon disulfide, oil of turpentine, carbon tetrachloride, fixed and volatile oils; slightly soluble in petroleum ether, hexane. The other link, ChemicalForums.com, seems to imply that it is soluble, but no data is given. Check out this for more on benzoic acid: http://en.wikipedia.org/wiki/Benzoic_acid
Does benzoic acid conduct electricity?
No, benzoic acid does not conduct electricity because it is a covalent compound that does not dissociate into ions in solution.
A mixture of camphor and benzoic acid can be easily separated by?
Benzoic acid is more soluble than camphor in ethanol. The solution can be filtrated.
What is normality of benzoic acid?
The normality of benzoic acid depends on its concentration in solution and its molecular weight. To calculate normality, you need the molarity of the solution and the number of equivalents of acid per mole of benzoic acid. Normality is equal to Molarity times Equivalent factor.
The benzoate anion is the conjugate base of the benzoic acid. Potassium benzoate forms a basic solution in water so benzoic acid is a?
weak acid.
What is the Amount of benzoic acid to be neutralized by 20 mL NaOH solution in both moles and grams?
To calculate the amount of benzoic acid to be neutralized, you need to know the molarity of the NaOH solution. If we assume a typical concentration of 0.1 M NaOH, then you would need 2 moles of benzoic acid (C6H5COOH) to neutralize 20 mL of the NaOH solution. In grams, this would be approximately 252 grams of benzoic acid (molecular weight of benzoic acid is 122.12 g/mol).
How do you separate benzoic acid from a mixture of CONGO RED and salt?
Dissolve the mixture in an apolar organic solvent, such as diethyl ether, and extract the acid with the addition of NaOH. The bezoic acid with ionize and go into the aqueous solution. Separate the two layers and add HCl to the aqueous layer to precipitate the benzoic acid. Wash the remaing ether solution with water and dry it with an anhydrous salt. Filter the ether solution and then remove the ether, the solvent, in order to obtain the pure benzoin.
