To test for the presence of phosphate (PO4 3-) in water, you can use the molybdenum blue method. This method involves adding ammonium molybdate followed by ascorbic acid and sulfuric acid to the sample, which forms a blue complex in the presence of phosphate ions. The intensity of the blue color is proportional to the phosphate concentration in the water sample.
The reaction between hydroxyapatite (Ca5(PO4)3OH) and an acid (HCl) can be shown as: Ca5(PO4)3OH + 3HCl -> 3CaCl2 + H3PO4 + H2O
The chemical equation is:3 FeCl2 + 2 K3PO4 = Fe3(PO4)2 + 6 KCl.
PO4^-3 is an ion.So its valency is -3
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
NH4(3)PO4, which is ammonium phosphate, is soluble in water. Ammonium salts are soluble.
No, the equation is: HPO4-2 → H+ + PO4-3 The HPO4-2 and PO4-3 are conjugate acid base pairs.
The reaction between hydroxyapatite (Ca5(PO4)3OH) and an acid (HCl) can be shown as: Ca5(PO4)3OH + 3HCl -> 3CaCl2 + H3PO4 + H2O
The reaction between potassium phosphate (K3PO4) and barium acetate (Ba(C2H3O2)2) will produce barium phosphate (Ba3(PO4)2) and potassium acetate (KCH3COO). The balanced chemical equation for this reaction is 3K3PO4 + Ba(C2H3O2)2 -> Ba3(PO4)2 + 6KCH3COO.
3Mg(s) + 2H3PO4(aq) ---> 3H2(g) + Mg3(PO4)2(s)I believe the equation is: Mg + H3PO4 ---> H2 + Mg3PO4. It should be Mg3(PO4)2 because magnesium has a charge of +2 (Mg+2), and phosphate has a charge of -3 (PO4-3), which would become Mg3(PO4)2. Balanced, the equation is 3Mg + 2H3PO4 ---> 3H2 + Mg3(PO4)2
phosphoric acid H3PO4 sodium hydroxide NaOH H3PO4 + 3NaOH = Na3PO4 + 3H2O 1 acid + 3 base = 1 salt + 3 water
The balanced chemical equation for this reaction is: 3H3PO4 + 6Ca(OH)2 -> 2Ca3(PO4)2 + 6H2O This balanced equation ensures that there is conservation of mass for each element present in the reaction.
The chemical formula for phosphate is PO4^3-.
The chemical equation is:3 FeCl2 + 2 K3PO4 = Fe3(PO4)2 + 6 KCl.
The balanced chemical equation for this reaction is: 2 Na3PO4 + 3 CaCl2 -> Ca3(PO4)2 + 6 NaCl
The net ionic equation for Na3PO4 is 3Na+ + PO4^3- -> Na3PO4. This equation shows that the sodium ion (Na+) and phosphate ion (PO4^3-) combine to form sodium phosphate (Na3PO4) without any spectator ions.
The net ionic equation for this reaction is:3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)How to get this answer:To write the net ionic equation, you can start with the molecular equation:2Na3PO4(aq) + 3Mg(NO3)2(aq) --> 6NaNO3(aq) + Mg3(PO4)2(s)The molecular equation can be used to write the full ionic equation. To do this, you break down everything that is aqueous into its ionic constituents:2Na+(aq) + 2PO43-(aq) + 3Mg2+(aq) + 6NO3-(aq) --> 6Na+(aq) + 6NO3-(aq) + Mg3(PO4)2(s)You can then cross out whatever is the same on both side to get your net ionic equation:3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)
The molecular equation for chromium (III) nitrate and potassium phosphate is: 2Cr(NO3)3 + 3K3PO4 -> Cr2(PO4)3 + 9KNO3