Unfortunately, you did not specify what final chemical equation you wanted given these formulas. From the data though I assumed the following: Fe2O3(s) + 3CO(g) à 2Fe(s) + 3CO2 H1 3Fe2O3(s) + CO(g) à 2Fe3O4(s) + CO2(g) H2 Fe3O4(s) + CO(g) à 3FeO(s) + CO2(g) H3 3(Fe2O3(s) + 3CO(g) à 2Fe(s) + 3CO2) 3(H1) 2Fe3O4(s) + CO2(g) à3Fe2O3(s) + CO(g) -H2 2(3FeO(s) + CO2(g) à Fe3O4(s) + CO(g)) 2(-H3) 3Fe2O3(s) + 9 (6)CO(g) à 6Fe(s) + 9(6)CO2 3(H1) 2Fe3O4(s) + CO2(g) à3Fe2O3(s) + CO(g) -H2 6FeO(s) + 2CO2(g) à 2Fe3O4(s) + 2CO(g) 2(-H3) 6FeO(s) + 6CO(g) à 6Fe(s) + 6CO2 3H1 + -H2 + -2H3 FeO(s) + CO(g) à Fe(s) + CO2 [(3H1 + -H2 + -2H3) / 6] FeO(s) + CO(g) à Fe(s) + CO2 -11KJ/mol
The reaction is:4 Fe + 3 O2= 2 Fe2O3
To calculate the mass of aluminum (Al) needed to completely react with 135 g of iron, you first need to determine the molar ratio between them from the balanced chemical equation. The balanced equation for the reaction between aluminum and iron is 2Al + 3Fe2O3 -> 3Fe + Al2O3. From this ratio, you can calculate that 2 moles of aluminum (Al) react with 3 moles of iron (Fe). Next, calculate the molar mass of aluminum (Al) and use it to convert the given mass of iron to moles. Finally, use the molar ratio to find the mass of aluminum needed.
To determine how many grams of Fe can be produced from 10.0 g of Al reacting with Fe2O3, we first need the balanced chemical equation for the reaction: [ 4Al + 3Fe2O3 \rightarrow 4Fe + 6Al2O3 ] From the equation, 4 moles of Al produce 4 moles of Fe. The molar mass of Al is approximately 27 g/mol, so 10.0 g of Al corresponds to about 0.37 moles of Al. This produces an equivalent of 0.37 moles of Fe. Given that the molar mass of Fe is about 56 g/mol, the mass of Fe produced is approximately (0.37 , \text{moles} \times 56 , \text{g/mol} \approx 20.72 , \text{g}).
3Fe2O3 + C =2Fe3O4 + CO Fe304 + C = 3Fe0 + CO FeO + C = Fe + CO 3Fe2O3 + CO = 2Fe3O4 + CO2 Fe3O4 + CO =3 FeO + CO2 FeO + CO = Fe + CO2 and C + CO2 = 2CO In this ways iron oxide get reduced to iron which is called sponge iron.
From the balanced chemical equation 3Fe2O3 + CO → 2Fe3O4 + CO2, it can be seen that 3 moles of Fe2O3 react with 1 mole of CO to produce 2 moles of Fe. Therefore, if 25 moles of CO react, it will produce 25/3 * 2 = 16.67 moles of Fe.
Oxides of iron can react with water and oxygen in the air to form rust, which is the hydrated form of iron oxide. This reaction is accelerated in the presence of electrolytes such as salts. Rusting of iron is a common example of a redox reaction where iron is oxidized and oxygen is reduced.
The reaction is:4 Fe + 3 O2= 2 Fe2O3
A possible reaction is:Fe2O3 + 6 K = 3 K2O + 2 Fe
The balanced equation for the reaction is: 3Fe2O3 + 3CO → 2Fe + 3CO2. This equation ensures that the number of atoms for each element is the same on both sides of the equation.
To calculate the mass of aluminum (Al) needed to completely react with 135 g of iron, you first need to determine the molar ratio between them from the balanced chemical equation. The balanced equation for the reaction between aluminum and iron is 2Al + 3Fe2O3 -> 3Fe + Al2O3. From this ratio, you can calculate that 2 moles of aluminum (Al) react with 3 moles of iron (Fe). Next, calculate the molar mass of aluminum (Al) and use it to convert the given mass of iron to moles. Finally, use the molar ratio to find the mass of aluminum needed.
Fe3O4 is the mineral magnetite, with aproper chemical name of Fe(II, III) oxide. it exhibits ferrimagnetism. It has iron atoms as FeII and FeIII. An old way of writing it was FeO.Fe2O3 The balanced equation for production from the elements is :- 3Fe + 2O2 -> Fe3O4 Commercially it is made by for example redung Fe2O3 with CO 3Fe2O3 + CO = 2Fe3O4 +CO2
Now a days,sponge iron is a household name in steel making process.There are different methods to manufacture sponge iron but in India largely coal based process are carried out.In this process iron ore lumps (5-20mm)are feed into a horizontaly inclined vessel named as Rotary kiln (length 40mt. and dia 3mt.) from one end with required quantity of coal(5-20mm).The kiln revolves in a certain rotation and during the travel time iron ore is reduced by coal and converted to sponge iron .To reduce the iron certain temperatures are maintained with the help of coal and air supplied through fans mounted in the kiln.The temp. are regulated by dampers provided with the fans. Some imp. reactions that take place inside the kiln are given below,The following reaction takes place inside the kiln.Fe2O3 + 3 CO = 2 Fe + CO2However the reduction from oxide to metal does not occurs in one step but by a gradual removal of oxygen giving rise to various intermediate oxides the reduction chain may be expressed as follows:2 Fe2O3 ------------------------- 2 Fe3O4 ------------------- 6 FeO -------------6 FeHematite Magnetite Wustite IronThe degree of reduction between each stage is as follows:11% 22% 67%3Fe2O3--------------------- 2Fe3O4-------------------------- 6FeO--------------6 FeThe byproduct of above reaction is carbon die oxide (CO2).This Co2 reacts with carbon from coal to produce CO.CO2 + C = 2 CO.The above reaction is known as bound ward reaction which is reversible.The above kiln dia and length can produce 100MT of sponge/day.Though all reaction takes place in solid state the product from the kiln transfered to a rotary drum called COOLER ,where sponge iron from the klin are cooled indirectly by water and temp. decreased from 1100˚C to 150˚C.Further the discharge material transfered to separation chamber by conveyor belts where magnetic sponge is separated from char by magnetic separators and stored in bunkers.With development and research production quantity also increased from 100MT TO 500MT by increasing the size of kilns.