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Explain why engines withequal power accelerate cars with a small mass quicker than cars with a large mass?

I hope your question is, "Why would the smaller car take less time to accelerate from 0 - 60 mph"?

Power measures the amount of energy provided per second. The energy provided is used to increase the velocity of the car (mass) to a specific velocity, 60mph. Since the change in velocity is the same for both cars, and Kinetic energy= ½ · mass · (velocity) 2, the greater the mass, the more energy needed to increase the velocity of the car to that specific velocity. Since Energy = Power · time, and power is constant, the only way to provide the more energy is to provide that same amount power for a longer period of time. For example, for a 10 kg car to reach a velocity of 5 m/s, requires ½ · 10 · 52 = 125 joules of energy. For a 20 kg car reach a velocity of 5 m/s, would requires ½ · 20 · 52 = 250 joules of energy. The energy is being supplied by a 25 Watt motor, which supplies 25 joules of energy per second. The 10 kg car requires 125 joules ÷ 25 joules per second, which will take 5 seconds. The 20 kg car requires 250 joules ÷ 25 joules per second, which will take 10 seconds.

Kinetic energy = ½ · mass · (velocity) 2, so change in Kinetic energy = ½ · mass · (velocityfinal2 -- velocityinitial2)

If we consider the car is accelerating from 0 - 60mph, velocityinitial = 0 mph, velocityfinal = 60mph

1. Change in Kinetic energy = ½ · mass · (velocityfinal) 2

2. Power = Change in Kinetic energy = ½ · mass · (velocityfinal) 2

time time

3. Power · time = ½ · mass · (velocityfinal) 2

See this web site to see picture and specs for the following car

http://www.leftlanenews.com/bugatti-veyron-16.4.html Bugatti Veyron 16.4 Grand Sport

Curb Weight (lbs) = 4470 lbs. Horsepower = 1001 @ 6000 rpm

Slug is the unit of mass in the English Measurement system, like Kilogram in the metric system.32.2 Slugs = 1 pound, so mass of car = 4470 ÷ 32.2 = 138.8 slugsUse Eq. 6 to determine the time for the car to accelerate from 0 -- 60 mph. 60 mph = 88ft/s

One mechanical horsepower = 550 foot-pounds per second.

4. (Powerfrom Engine) · time = 0.5 · mass · (velocityfinal)2

5. (# of Hp) · 550 ft-lbs/s- Hp · (time ) = 0.5· ( # of slugs) · ( 88 ft/s)2

6. 1000 Hp · 550 ft-lbs./s- Hp· (time ) = (0.5) ·(138.8 slugs) · ( 88 ft/s)2

Timesec = 0.98 seconds

According to the equation, the time to accelerate from 0 to 60 mph = 0.98 sec According to the Car website below, time to accelerate from 0 to 60 mph = 2.6 sec

http://www.leftlanenews.com/bugatti-veyron-16.4.html

The car loses some of the energy as it spins its tires taking off. The 0.98 second time is for a 100% efficient situation. Any heat given off is a loss of energy. At 6000 rpm, the engine, the transmission and other parts of the drive train are getting hot.

Now let, try the same problem for a car of ½ the mass = ½ of 138.8slugs = 69.4 slugs and the same power.

7. 1000 Hp ·550 ft-lbs./ s- Hp · (time) = 0.5 · 69.4 slugs · ( 88 m/s)2 timesec = 0.49 Timesec = 0.49 seconds

Notice the only number that changed from the equation for the first car was the mass and as a result the time changed. Notice car2 has half the mass as car1, so it took half the time to accelerate 0-60 mph! The less mass, the easier to accelerate, so the less time needed to accelerate with a constant amount of power. In physics, we say that the time and power are directly related. Since these 4 numbers: 1000 Hp, 550 ft-lbs./ s- Hp , 0.5, and 88 ft/s are constants, the only numbers that will change are the mass and the time. We can set up a proportion.

Masscar 1 timecar 1

Masscar 2 = timecar 2

138.8 slugs 0.98 seconds

69.4 slugs = (timecar2)

Use this proportion to solve for timecar2 = ________ seconds

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