That is how specific heat is defined. When you measure something you have to measure it relative to some point of reference. In specific heat it was agreed upon that water was to be the standard and its specific heat would be one. Therefore everything else is measured relative to water.
The specific latent heat of ice and water is not the same. The specific latent heat of fusion for ice (the heat required to convert ice to water at 0°C) is approximately 334 kJ/kg, while the specific latent heat of vaporization for water (the heat required to convert water to vapor at 100°C) is significantly higher, around 2260 kJ/kg. Thus, the energy required for phase changes differs between ice and water.
Temp is the same, the quantity of heat is not.
The specific heat of water is different from the specific heat of ice and so 'wet ice' into a calorimeter experiment can increase the mass of water in the calorimeter and become a source of unaccuracy.
Coldness is a lack of heat energy, so, if you take two cups of water under the same conditions, add ice to one of them, and add the same amount of room-temperature water to the other, the cup with ice will have less heat energy. However, the environment around it will eventually heat up that cup, so they will both be the same temperature.
To calculate the heat required to convert ice to liquid at a temperature of 14.7°C, we first need to heat the ice from -12.1°C to 0°C, using the specific heat capacity of ice. Then we calculate the heat required to melt the ice at 0°C to water at 0°C, using the heat of fusion of ice. Finally, we calculate the heat required to heat the water from 0°C to 14.7°C, using the specific heat capacity of water. By performing these calculations, we can determine if the available heat of 4390 J is sufficient.
The specific latent heat of ice and water is not the same. The specific latent heat of fusion for ice (the heat required to convert ice to water at 0°C) is approximately 334 kJ/kg, while the specific latent heat of vaporization for water (the heat required to convert water to vapor at 100°C) is significantly higher, around 2260 kJ/kg. Thus, the energy required for phase changes differs between ice and water.
Ice melts faster in water compared to alcohol because water has a higher specific heat capacity and thermal conductivity, allowing it to transfer heat more efficiently to the ice and accelerate the melting process. Alcohol has a lower specific heat capacity and thermal conductivity, so it is less effective at transferring heat to the ice.
it doesnt, water has the same specific heat no matter what temperature it is at...about 4.18. Specific heat is a characteristic value of materials to resist changes in temperature (heat flow). Please rephrase the question if this is not the answer you are after
The heat required to vaporize 500 grams of ice at its freezing point is the sum of the heat required to raise the temperature of the ice to its melting point, the heat of fusion to melt the ice, the heat required to raise the temperature of water to its boiling point, and finally the heat of vaporization to vaporize the water. The specific heat capacity of ice, heat of fusion of ice, specific heat capacity of water, and heat of vaporization of water are all needed to perform the calculations.
When you drop a block of ice in boiling water, heat from the water will transfer to the ice, causing the ice to melt. The heat will continue to transfer from the water to the ice until the ice completely melts and reaches the same temperature as the water.
Temp is the same, the quantity of heat is not.
To calculate the heat needed to change ice to water, we use the specific heat capacities and latent heat of fusion. First, calculate the heat needed to raise the temperature of 565 g of ice from -13°C to 0°C using specific heat capacity of ice. Then, calculate the heat needed to melt the ice at 0°C to water at 0°C using the latent heat of fusion for ice. Finally, calculate the heat needed to raise the temperature of water from 0°C to 20°C using the specific heat capacity of water. Add these three values together to find the total heat required.
The specific heat of water is different from the specific heat of ice and so 'wet ice' into a calorimeter experiment can increase the mass of water in the calorimeter and become a source of unaccuracy.
Ice will melt faster in water than in milk due to the difference in thermal conductivity and specific heat capacity of the two liquids. Water has a higher thermal conductivity and specific heat capacity compared to milk, allowing it to transfer heat more efficiently to the ice and melt it faster.
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
The heat required to convert ice at 0°C to water at 0°C is known as the latent heat of fusion. For water, this value is 334 J/g. Therefore, to convert 0.3 g of ice to water at the same temperature, the heat required is 0.3 g * 334 J/g = 100.2 Joules.
To calculate the energy required to heat and vaporize the ice, you need to consider the heat needed for each step: Heat the ice from -35°C to 0°C (specific heat of ice). Melt the ice at 0°C (heat of fusion). Heat the water at 0°C to 100°C (specific heat of water). Vaporize the water at 100°C (heat of vaporization). Heat the steam from 100°C to 110°C (specific heat of steam). Adding all these energies together will give you the total energy required.