Dissolve in water more than 320 g of the anhydrous salt, at 20 0C.
The solution of CuSO4 is blue.The solution of FeSO4 is green.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
One common method to separate hydrated CuSO4 from its aqueous solution is through the process of evaporation. By heating the solution, water evaporates leaving behind solid CuSO4. The solid can then be filtered to separate it from the remaining liquid.
Evaporating a copper sulphate solution you can obtain anhydrous crystals of CuSO4. Increasing the temperature CuSO4 will be thermally dissociated.
Acidified CuSO4 is used as a reagent in the Fehling's test to detect the presence of reducing sugars in a solution. When a reducing sugar is present, it reduces the blue Cu2+ ions in the CuSO4 solution to red-brown Cu2O precipitate, indicating a positive result.
The weight/weight of CuSO4 in the saturated solution is 20%. This means that for every 100 grams of the solution, 20 grams are CuSO4.
The solution of CuSO4 is blue.The solution of FeSO4 is green.
CuSO4 - is a super saturated salt.
BY adding excess Filter off excess MgCO3(s) . heat the filter to get a saturated solution , cool to obtain crystals , filter . H2SO4(aq)+MgCO3(s)--->MgSO4(aq)+H2CO3(g)
NO such formula as ' cuso4 ' . If you mean ' Copper sulphate' then the formula is ' CuSO4 ' NOTE the use of capital letters. See my note below!!!!! The colour of aqueous CuSO4 is BLUE. NB When writing chemical formula. #1 Single letter elemental symbols are ALWAYS a CAPITAL letter. #2 Double letter elemental symbols are first letter is a capital letter, and the second letter is small/lower case. This is the International recognised symbolism and as shown in the Periodic Table. It is done to avoid confusion!!! ' CO ' is carbon monoxide ' Co' is cobalt. Hence Copper is 'Cu' NOT 'cu' Sulphur is 'S' NOT 's' Oxygen is 'O' NOT 'o'.
Take 159.6 mg white, anhydrous CuSO4 or 249.7 mg blue pentahydrate (CuSO4.5H2O), dissolve in 90 mL distillled water, add 1 mL diluted ammonia (1M NH3) and finally fill up to exactly 100.0 mL with distilled water to get the final 10mM alkaline (ammoniacal) CuSO4solution.
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
One common method to separate hydrated CuSO4 from its aqueous solution is through the process of evaporation. By heating the solution, water evaporates leaving behind solid CuSO4. The solid can then be filtered to separate it from the remaining liquid.
RMM of CuSo4 . 5H2O = 160 + 5x18 = 250 g How much contain gram in 100 mL of 0.050 M CuSO4 solution is - Solution: = 0.050 x 100/1000 x 250 = 0.050x4 (100)/ 16 = 1.25 g
Evaporating a copper sulphate solution you can obtain anhydrous crystals of CuSO4. Increasing the temperature CuSO4 will be thermally dissociated.
Phosphorus does not react with aqueous CuSO4. Copper sulfate solution is a salt solution and does not react with phosphorus to produce any significant chemical reaction.