For example, with an appropriate densimeter.
For the density of glycerol see this link.
Density of glycerol (propan-1,2,3-triol) is 1.261 g/cm³
The graph will be a straight graph if you plot r2 against v. If we calculate the gradient of the line this is giving us the value of the constant "k" from the equation: k = v r2 With this calculated value of "k" we can calculate the value of the viscosity of the liquid using: Viscosity = 2(Denisity of sphere - Denisty of Glycerol) g 9k
The 3 hydroxyl groups in glycerine/glycerol form intermolecular hydrogen bonds. this strong intermolecular attractions causes it to be a viscous liquid.
To find the molarity, we need to first calculate the number of moles of glycerol using its density at 15°C, which is 1.260 g/mL. Then, convert the mass of glycerol to moles using its molar mass of about 92.09 g/mol. Finally, divide the moles by the total volume of the solution in liters (200.00 mL = 0.200 L) to get the molarity.
First, calculate the mass of glycerol in 100g of the solution: 48.0g glycerol/100g solution = 48.0%. Next, calculate the mass of water in 100g of the solution: (100g - 48.0g glycerol) = 52.0g of water. Calculate the moles of glycerol by dividing the mass of glycerol by its molar mass: 48.0g / 92.09g/mol = 0.521 mol. Calculate the molality by dividing the moles of solute by the mass of solvent in kg: 0.521 mol / 0.052 kg = 10 mol/kg.
For the density of glycerol see this link.
Density of glycerol (propan-1,2,3-triol) is 1.261 g/cm³
The density of glycerol at 20 degrees Celsius is approximately 1.26 g/cm3. The viscosity of glycerol at 20 degrees Celsius is around 1.49 centipoise.
The graph will be a straight graph if you plot r2 against v. If we calculate the gradient of the line this is giving us the value of the constant "k" from the equation: k = v r2 With this calculated value of "k" we can calculate the value of the viscosity of the liquid using: Viscosity = 2(Denisity of sphere - Denisty of Glycerol) g 9k
The 3 hydroxyl groups in glycerine/glycerol form intermolecular hydrogen bonds. this strong intermolecular attractions causes it to be a viscous liquid.
Density is calculated by dividing the mass of a substance by its volume. To find the density of glycerol in this case, you would need to know the mass in grams. Once you have the mass in grams, you can divide it by the volume in liters (3.25) to find the density.
To find the molarity, we need to first calculate the number of moles of glycerol using its density at 15°C, which is 1.260 g/mL. Then, convert the mass of glycerol to moles using its molar mass of about 92.09 g/mol. Finally, divide the moles by the total volume of the solution in liters (200.00 mL = 0.200 L) to get the molarity.
Corn syrup would settle below glycerol (glycerol would be on top) because the density of corn syrup is greater than that of glycerol
The dennsity of glycerine is 1,261 g/cm3.
You can't get volume in centimetres, only in centimetres cubed. Density is calculated using the formula Density= Mass/Volume So if the mass of an object was 10 grams and its volume 5 centimetres cubed, its density would equal two grams per cubic centimetre. d=m/v d=10/5 Density= 2 g/cm3 Also, some simple conversions are 1 cm3 = 1 mL and 1 m3 = 1000 L
It is 1244.3 kg per cubic metre (= 1.2443 grams per ml).