0
What else can I help you with?
How is hfusion used to calculate the energy required to vaporize a volume of liquid?
Liters liquid 1000ml/1L g/ml mol/g Hfusion
What volume of a 0.550 M solution of potassium hydroxide can be made with 10.7g of potassium hydroxide?
To calculate the volume, first find the number of moles of potassium hydroxide using its molar mass. Then use the molarity to calculate the volume. Calculate moles of KOH: 10.7g / 56.11g/mol = 0.191 moles KOH Volume = moles / Molarity = 0.191 moles / 0.550 mol/L = 0.348 L = 348 mL
What mass of KI is present in 276 mL of a 0.50 M solution?
To calculate the mass of KI in the solution, first calculate the number of moles of KI present using the formula moles = Molarity x Volume (in liters). Then, use the molar mass of KI (potassium iodide) to convert moles to grams. The molar mass of KI is 166 g/mol.
If 25.5mg of oxalic acid dihydrate are dissolved in 1.00 ml of solution what is the molarity of the resulting solution?
To calculate the molarity, you need to know the molar mass of oxalic acid dihydrate (C2H2O4•2H2O) which is approximately 126.07 g/mol. First, convert 25.5 mg to grams (0.0255 g), then calculate the number of moles using the molar mass. Next, divide the number of moles by the volume of solution in liters (1.00 ml = 0.001 L) to find the molarity which is 0.255 M.
Calculate how many grams of NaCl is required to make 200.0 mL of a 0.125 M solution?
To calculate the grams of NaCl needed to make a 0.125 M solution in 200.0 mL, use the formula: moles = Molarity x Volume (L). First, convert 200.0 mL to 0.2 L. Then, calculate moles: 0.125 mol/L x 0.2 L = 0.025 moles of NaCl. Finally, convert moles to grams by multiplying by the molar mass of NaCl (58.44 g/mol): 0.025 moles x 58.44 g/mol = 1.46 grams of NaCl.
Calculate the molarity of a solution of potassium permanganate and density is 1.04 gmL which contans 15.00 percent by mass?
C [mol/L] = w% * rho [g/mL] *1000 [mL/L] / (100% * M [g/mol] ) = = w% * rho [g/mL] *10 [mL/L%] / ( M [g/mol] ) = = 15.00 % * 1.04 [g/mL] *10 [mL/L%] / ( 158.034 [g/mol] ) = = 0.987 [mol/L] the molarity of the solution of potassium [in mol per liter] equals the content of KMnO4 by mass in percents multiply by density in g/mL multiply by 10 [mL/(L*%)] divide by molar mass of KMnO4 (M = 158.034 g/mol) This gives 0.987 mol/L. Thus the molarity equals approximately 1 M.
How many milliliter is 80mg?
ml is a size for an amount of fluid. mg is a size for a mass. You can convert ml in mg if you know the material your dealing with. Then you need the periodic system of elements and calculate the molecular weight of you material knowing; mol(n) = mass(mg) / molecular weight(g) then calculate the volume (ml) =mol(n) / concentration(c)
What volume of a 0.357 M hydrochloric acid solution is required to neutralize 24.3 mL of a 0.200 M potassium hydroxide solution?
To neutralize the potassium hydroxide, the moles of HCl should equal the moles of KOH. First, calculate the moles of KOH: 0.24.3 mL * 0.200 mol/L = 0.00486 mol. Since the ratio of HCl:KOH is 1:1, you need 0.00486 mol of HCl. Finally, calculate the volume of 0.357 M HCl needed: Volume = 0.00486 mol / 0.357 mol/L ≈ 0.014 L or 14 mL.
What is the molarity of 22.5 g of MgS in 817 ml of solution?
To calculate molarity, you first need to determine the number of moles of MgS. Calculate the molar mass of MgS: Mg: 24.3 g/mol S: 32.1 g/mol Molar mass of MgS = 24.3 g/mol + 32.1 g/mol = 56.4 g/mol Number of moles of MgS: 22.5 g / 56.4 g/mol = 0.398 moles Calculate molarity: Molarity = moles / volume of solution (in liters) Molarity = 0.398 moles / (817 ml / 1000) = 0.487 M
What is the number of moles of NaOH in 16.5 mL of 0.750 Molar NaOH?
To find the number of moles of NaOH, first convert the volume from mL to L (16.5 mL = 0.0165 L). Then, use the formula moles = concentration (mol/L) × volume (L) to calculate the moles of NaOH. Plugging in the values: 0.750 mol/L × 0.0165 L = 0.0124 moles of NaOH.
How is hfusion used to calculate the energy required to vaporize a volume of liquid?
Liters liquid 1000ml/1L g/ml mol/g Hfusion
Calculate the volume of a 0.05000 mol/l stock solution of CuSO4 (aq) required to prepare 100.0 ml of a 0.005000 mol/l solution?
For starters, you know that 0.05000-mol L − 1 solution of copper(II) sulfate contains 0.05000 moles of copper(II) sulfate, the solute, for every 1 L = 10 3 mL of the solution.
What is the molarity of 930 mL of LiCl solution that contains 139.9 g of LiCl?
To calculate the molarity, first convert the mass of LiCl to moles using its molar mass (6.94 g/mol for Li, 35.45 g/mol for Cl). Then, divide the moles of LiCl by the volume in liters (930 mL = 0.93 L) to get the molarity. The molarity of the solution would be around 5.2 mol/L.
What volume of a 0.550 M solution of potassium hydroxide can be made with 10.7g of potassium hydroxide?
To calculate the volume, first find the number of moles of potassium hydroxide using its molar mass. Then use the molarity to calculate the volume. Calculate moles of KOH: 10.7g / 56.11g/mol = 0.191 moles KOH Volume = moles / Molarity = 0.191 moles / 0.550 mol/L = 0.348 L = 348 mL
What mass of KI is present in 276 mL of a 0.50 M solution?
To calculate the mass of KI in the solution, first calculate the number of moles of KI present using the formula moles = Molarity x Volume (in liters). Then, use the molar mass of KI (potassium iodide) to convert moles to grams. The molar mass of KI is 166 g/mol.
How many grams of H3PO4 are in 265 ml of a 1.50 M solution of H3PO4?
To find the grams of H3PO4 in 265 ml of a 1.50 M solution, you first calculate the moles of H3PO4 using the molarity (1.50 mol/L) and volume (0.265 L), then convert moles to grams using the molar mass of H3PO4 (98.0 g/mol). Therefore, there would be approximately 39.2 grams of H3PO4 in 265 ml of the solution.
What mass of KOH is needed to make 400 mL of 0.725 M KOH?
To calculate the mass of KOH needed, you can use the formula: mass (g) = volume (L) x molarity (mol/L) x molar mass (g/mol) First, convert the volume of 400 mL to liters (400 mL = 0.4 L). Then, plug in the values: mass = 0.4 L x 0.725 mol/L x 56.11 g/mol = 16.07 grams. Therefore, you would need 16.07 grams of KOH to make 400 mL of 0.725 M solution.
