0.0165 (L) * 0.750 (mol/L) = 0.0124 mol NaOH in 16.5 mL
mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH
The solution has a molar concentration of 0,33.
I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1
Need total molar mass sodium hydroxide which you can easily get from your periodic table. 2.2 moles NaOH (39.998 grams/1 mole NaOH) = 88 grams in mass ==============
The molar weight of NaOH is approx. 40 g/molSo 12.0 g of NaOH would be approx 12/40 = 0.3 mol NaOH
mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
The solution has a molar concentration of 0,33.
The number of moles is 0,0038.
I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1
Need total molar mass sodium hydroxide which you can easily get from your periodic table. 2.2 moles NaOH (39.998 grams/1 mole NaOH) = 88 grams in mass ==============
The molar weight of NaOH is approx. 40 g/molSo 12.0 g of NaOH would be approx 12/40 = 0.3 mol NaOH
Molar mass of NaOH is 39.998 grams. So, 2.75 mol NaOH (39.998g NaOH/1 mol NaOH) = 109.9945 grams NaOH ( you do the sigi figi )
The number of moles is 1,8.
The same number of moles for each.
First of all, it is HCl solution, more properly hydrochloric acid (that is HC l ). It is composed of hydrogen (H) and chlorine (Cl). The answer depends on the volume of the acid and the concentration of the alkali. Here is a sample calculation with some random values for the variables you have not given. If the HCl is neutralized by 25.0 ml of 0.500 M NaOH, then the number of moles of NaOH equals the number of moles of HCl. 25 ml is equal to 0.025 liters, and since molarity is moles per liter we have: Moles of NaOH = 0.0250 Liters * 0.500 moles/liter = 0.0125 moles Moles of NaOH = moles of HCl = 0.0125 moles If there are 0.0125 moles HCl in 45.0 ml (or 0.045 L), then the molarity of the HCl is: 0.0125 moles ÷ 0.0450 L = 0.278 moles/L = 0.278 M HCl
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution