The molar weight of NaOH is approx. 40 g/mol
So 12.0 g of NaOH would be approx 12/40 = 0.3 mol NaOH
0.75 moles in 30.0g of NaOH.
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
You need 2,4 g NaOH (0,06 moles).
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
0.75 moles in 30.0g of NaOH.
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
Molecular mass of NaOH= 40.0 grams9.40 grams / (40.0 grams) = .235 moles NaOH
M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
You need 2,4 g NaOH (0,06 moles).
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
0,15 moles NaOH contain 6 g.
2.00 M NaOH = 2 moles NaOH/litermolar mass NaOH = 40 g/mole2 moles/liter x 40 g/mole = 80 g/liter(x L)(80 g/L) = 32.0 gx = 0.4 liters = 400 mls needed
First determine the mass of 2 lbs of NaOH - it's about 2 x 454 g = 908 g[Having to use a conversion factor introduces error.]A mole of NaOH is 40 g; 908 g/40 g/mole = 22.7 moles.
120 g calcium is equal to 3 moles.