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Gas stored in a tank at 273 K has a pressure of 388 kPa. The safe limit for the pressure is 825 kPa. At what temperature will the gas reach this pressure?

Using the combined gas law (P1/T1 = P2/T2), we can calculate the new temperature at the safe limit pressure: (388 kPa / 273 K) = (825 kPa / T2) T2 = 273 K * (825 kPa / 388 kPa) T2 = 578 K Therefore, the gas will reach a pressure of 825 kPa at a temperature of 578 K.


If a gas in a seal container has a pressure of 50 kPa at 300 k what will the pressure be if the temperature rises to 360 k?

60kpa


What if gas is in a sealed container has a pressure of 50 k pa at 300 k what will the pressure be if the temperature rises 360 k?

60kpa


A quantity of a gas has an absolute pressure of 400kPa and an absolute temperature of 110 degrees kelvinwhen the temperature of the gas is raised to 235degrees kelvin what is the pressure of the gas?

Using the combined gas law (P1/T1 = P2/T2), we can calculate the pressure of the gas at the new temperature. Plugging in the values, we get P2 = (P1 * T2) / T1 = (400 kPa * 235 K) / 110 K = 853 kPa. Therefore, the pressure of the gas is 853 kPa when the temperature is raised to 235 degrees Kelvin.


When a gas of 3.4 moles occupies a volume of 40.6 L at 298 K what is the pressure of the gas in kPa?

The ideal gas law equation can be used to calculate the pressure of the gas. (PV = nRT), where (P) is pressure, (V) is volume, (n) is the number of moles, (R) is the gas constant, and (T) is the temperature in Kelvin. Rearranging the formula, (P = \frac{nRT}{V}), substituting the given values into the equation, we get (P = \frac{(3.4 mol)(8.31 kPa⋅L/mol⋅K)(298 K)}{40.6 L}), which results in a pressure of approximately 638 kPa.


A tire has a pressure of 325 kPa at ten degrees Celsius. If the temperature rises fifty degrees Celsius and the volume remains constant what is the new pressure?

Use the ideal gas law: P1/T1 = P2/T2. Rearrange the equation to solve for P2: P2 = (P1/T1) * T2. Plug in the values: P2 = (325 kPa / 283 K) * 60 degrees Celsius. Convert the temperature to Kelvin: 60 degrees Celsius + 273 = 333 K. Calculate the new pressure: P2 ≈ 361 kPa.


A gas is measured at room temperature 24 deg C and is found to have a pressure of 100.0 kPa What is the new pressure if the gas is cooled to standard temperature O K?

LESS


What temperature and pressure are defined as Standard Temperature and Pressure?

Usually we use a temperature of 20 °C and an absolute pressure of 101.325 kPa for 1 atmosphere.


What are the standard conditions for gas measurements?

These data are very variable around the world.- IUPAC recommendations:a) 0 oC and 100 kPa orb) 25 oC and 100 kPa- NIST recommendation:20 0 oC and 101,325 kPa- methane gas measurements: 15 oCand other values also exist.


Standard temperature and pressure are defined as?

IUPAC defines STP as 273.15 K and 100 kPa.


A gas in a sealed container has a pressure of 125 kPa at a temperature of 30.0 degrees celsius If the pressure in the container is increased to 201kPa what is the new temperature?

Using the ideal gas law (P1/T1 = P2/T2), we can set up the equation as: 125 kPa / (30.0 + 273.15 K) = 201 kPa / T2. Solving for T2, the new temperature would be approximately 57.7 degrees Celsius.


What does STP stand for in chemistry?

It means Standard Temperature and Pressure.-Standard temperature is equal to 0 °C, which is 273 K.-Standard pressure is equal to 1 atm 760 mmhg or torr and 101.3 KPa.