You can determine the amps of any power consuming source by dividing the watts by the volts. Example: If the bulb is 60 watts and your volts are 120, then 60/120 = .5 amps. Or you could use an amp probe.
To calculate the current, you can use the formula: current (in amps) = power (in watts) / voltage (in volts). So, for a 50W halogen lamp operating at 12V, the current draw would be approximately 4.17 amps (50W / 12V = 4.17A).
A 230 watt linear halogen lamp should be replaced by a 230 watt linear halogen lamp if the same brightness is required.
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No problem because the 200 watt produces less heat.
LEDs and CFLs use about a quarter of a halogen so the answer is 35-40 watts.
1.67 Amps
To calculate the current, you can use the formula: current (in amps) = power (in watts) / voltage (in volts). So, for a 50W halogen lamp operating at 12V, the current draw would be approximately 4.17 amps (50W / 12V = 4.17A).
A 230 watt linear halogen lamp should be replaced by a 230 watt linear halogen lamp if the same brightness is required.
The purpose of halogen gas in a tungsten-halogen lamp is to increase the lifespan and efficiency of the lamp. The halogen gas helps to recycle evaporated tungsten back onto the filament, preventing blackening of the glass and extending the life of the lamp.
There is no halogen microwave. There is a halogen microwave oven bulb. (The technical term for a "bulb" is a lamp.) Some microwave ovens use a halogen lamp to light up the oven cavity. Replacing them is similar to replacing a "regular" incandescent lamp, except that when halogen lamps are being replaced, it is critical not to touch the lamp with bare fingers. Leaving skin oils on a halogen lamp shortens the lamp life and can set up a dangerous situation where the lamp might overheat.
The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
xenon(Z NON) halogen(HAL O JEN)
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It would be pretty much undefined, since the filament of the halogen bulb would fail immediately then there would be an open circuit with no current draw. <<>> The formula for current is Amps = Watts/Volts. The lamp itself would draw 4.16 amps. Since the voltage of the lamp is 12 volts there is a internal transformer involved in the fixture itself. It doesn't matter what the input (primary) voltage to the transformer is, so long as it meets the manufacturer's specification as to the proper voltage to operate the fixture.
It is a double ended halogen bulb and I do not know how to get to it to release it from the lamp.
1909
No problem because the 200 watt produces less heat.